To determine how far from the base of the cliff the keys land, we need to know the height of the cliff and the initial conditions of the keys’ fall, such as any horizontal motion if applicable. Assuming the keys are dropped straight down with no initial horizontal velocity, they will land directly at the base of the cliff. However, if there is an initial horizontal velocity, we would need to calculate the time of fall and the horizontal distance covered during that time to find the exact landing point.
64 METERSA+
64 metersIf a ball is thrown horizontally at 20 m/s from the top of a cliff that is 50 meters high, the ball will strike the ground 64 m from the base of the cliff (20m/s x 3.2 s).
Time to reach the bottom would be got from t = ./(2 * 54 / 9.8) = 3.32 s Here the horizontal component of the velocity would remain the same. So the horizontal range is got right from 9 * 3.32 = 29.88 m. So we could find the key at a distance of 30 m right from the base of cliff.
Use the tangent ratio to solve this problem because in effect you have the outline of a right angle triangle: tan = opp/adj adj = opp/tan adj = 60.50/tan 20.24 degrees The boat is 164.0806104 (or 164)) metres from the base of the cliff.
far
4.0m
about 260 miles
60m deep
Piano keys at the far left.
The Keys are 120 miles long. Raleigh to Key West is 957 miles.
Angle of depression equals angle of elevation (alternate angles) So use the tangent ratio to find the distance of the two ships are from the base of the cliff: 104.6672838 - 83.36285007 = 21.30443373 meters apart.
The best place would be far away from a cliff and the worst would be right on top of a cliff or some sort of land such as a beach or dierectly beneath it. At anytime, gravity will cause mass waisting, anotherwords the rock and soil will just break apart.