30
3
-3*radical(2)*radical(50) = -3*radical(2*50) = -3*radical(100) = -3*10 = -30
√18
1 squared radical 40 is equal to 1 squared radical (4 x 10), and this become 2 squared radical 10. By adding 2 squared radical10 with 3 squared radical 10 we get 5 squared radical 10.
The number 300 can be simplified as a radical by factoring it into its prime factors: (300 = 100 \times 3 = 10^2 \times 3). Therefore, the square root of 300 can be expressed as ( \sqrt{300} = \sqrt{100 \times 3} = \sqrt{100} \times \sqrt{3} = 10\sqrt{3}). Thus, the simplified form of 300 as a radical is (10\sqrt{3}).
15√10
radical (64/3) or 8/sqrt(3)
First, note that radical 4 is 2. So 3xradical 4 is just 6, Now we have 6+2 radical 3. You can't do much with this except factor out a 2 if you want 2(3+Radical 3)
3√250 = 15√10 The cube root of 250 is 5 times the cube root of 2.
radical 3 or 6
3 times the square root of 10
Radical (3x) = radical(x) * radical(3).