To draw the Lewis structure of 2CO2, you first need to determine the total number of valence electrons. Each oxygen atom contributes 6 valence electrons, and each carbon atom contributes 4 valence electrons, for a total of 16 + 4 = 20 valence electrons. Place the carbon atom in the center, surrounded by two oxygen atoms. Each oxygen atom forms a double bond with the carbon atom, using 4 electrons each. This leaves 4 electrons to be placed as lone pairs on each oxygen atom to satisfy the octet rule.
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The half reaction for the given chemical equation 2CO + O2 -> 2CO2 is: 2CO -> 2CO2 (in acidic medium) 2CO -> 2CO2 + 2H2O + 2e- (in basic medium)
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It is: C2H5OH+3O2 ----> 2CO2+3H2O
C2H5OH +3O2 gives 2CO2 +3H2O ...it burns with ablue flame in air
2c2h5oh + 7o2 --> 2co2 + 3h2o
C2H5OH + 3O2 ----> 2CO2 + 3H2O
The reaction equation for the oxidation of acetylene (C2H2) with nitrous oxide (N2O) is: 2C2H2 + N2O -> 2CO2 + H2O + N2
There are 4 oxygen atoms in the formula 2CO2. Each CO2 molecule contains 2 oxygen atoms, so when you have 2 CO2 molecules, you get a total of 4 oxygen atoms.
C2h4 + o2 ------------- co2 + h2o c2h4 + 3o2 ------------- 2co2 + 2h2o
C6H12O6---> 2C2H5OH + 2CO2
C6H12O6+zymase+yeast---> 2 C2H5OH+2CO2+ENERGY
2CO + O2 --> 2CO2