You just have to divide the watts by the voltage to find the amps. For example 60 watts on a 120 v system would take ½ amp.
An incandescent nightlight bulb is either 4 watt or 7 watt. A 4 watt bulb uses 1/25th (0.04) the power of a 100 watt bulb. A 7 watt bulb uses 7/100th (0.07) the power of a 100 watt bulb. There are LED and other types of nightlights that use much less power than this. To find the energy total used multiply the power (in watts) by the total time the light is on (in hours) to get energy (in Wh). If you want kWh divide this by 1000 as a watt is 1/1000th of a kW.
Depend on watt and voltage use of light bulbs. You can use this ohm's law formular to calculate the current draw on light bulbs. I (current in amp) = P (watt)/ E (voltage) If 25W light bulb use in 115V AC (resident home) then current draw will be: 25/115 = 0.22A or 22 miliamperes. Hope this help.
Fuses are not rated in wattage, they are rated in amperage and voltage.
In general no, because the extra heat produced would make it a fire hazard.
A lumen is a unit of luminous flux, which is the amount of light emitted per unit time. A watt is a unit of power (such as electrical power), which is the amount of energy consumed per unit time. Light bulbs have ratings in watts, which measures how much electricity they use, and lumens, which measures how much light they give off. For the same kind of bulb (incandescent, fluorescent, LED, etc.), a bulb with a higher wattage will produce more lumens. However, a 10-watt LED or compact fluorescent bulb may produce more lumens than a 40-watt incandescent bulb.
To calculate the amperage of a 40-watt bulb, you need to use the formula: Amps = Watts / Volts. If the bulb operates at 120 volts (standard for US households), the amperage will be 0.33 amps (40 watts / 120 volts).
The amps drawn by a 65 watt light bulb should be 65/120 or 0.54167. This fraction of an ampere may be restated as 541.67 milli-amps.
Watts = Volts X Amps. Amps=Watt / Volts. So, with a 240V mains, a 60W bulb draws 0.25amps. On a 12 system (car/auto) a 60W bulb draws 5 amps. On a 110V mains, a 60W bulb draws .55 Amps.
There are zero amps in a 300 watt bulb. Watts are the product of amps times volts. W = A x V. To find amperage use the equation A = W/V. If you find the voltage of the 300 watt bulb uses, divide the wattage by the voltage and it will give you the amps of a 300 watt bulb.
Amps x volts = watts So, assuming you are running on 110 volt line, the answer is 65 watts/110 volts=.591 amps.
To find the current in amps for a 50-watt light bulb, you can use the formula ( I = \frac{P}{V} ), where ( I ) is the current in amps, ( P ) is the power in watts, and ( V ) is the voltage in volts. For example, if the bulb operates at 120 volts, the current would be ( \frac{50}{120} ), which equals approximately 0.42 amps. If the bulb operates at a different voltage, simply adjust the voltage in the formula accordingly.
The formula for finding amperage is I = W/E. Amps = Watts/Volts. Without the value of the voltage to the bulb this question can not be answered.
To calculate the amperage, you can use Ohm's Law formula: Amperage (A) = Power (W) / Voltage (V). In this case, for a 5 watt bulb at 12 volts, the amperage drawn would be 0.42 amps (5W / 12V = 0.42A).
A 13W bulb consumes 13W/110V=0.118 A.If you use it for an hour, it consumes 0.118 Ah, for 2 hours 0.236 Ah, and so on..AnswerLamps don't use ampere hours, as this is simply a unit of measurement for electric charge. You probably mean 'watt hours' which is a measure of energy. A 13-W lamp will use 13 Wh for each hour it is used.
Current (amps) = power (watts) / voltage = 100/240 = 0.42 amps
On this calculation I am assuming that the light bulb is using a 120 volt source. Watts = Amps x Volts. Amps = Watts/Volts, 40/120 = .33 amps. R = Volts/Amps, 120/.33 = 363.6 ohms resistance in the 40 watt light bulb.
depending on voltage supplying the bulb, each ballast spicifies on it such rating. many ballasts have better efficiency at higher voltage. however; say 175 watt bulb, 120V with 80% efficiency= (175/120)/.8=1.82amps