Suppose a digital camera has a storage capacity of 256 MB.How many photographs could be stored in the camera if each consisted of 1024 pixels per row and 1024 pixels per column?

Answer 1

Given a digital camera has a storage capacity of 256MB. That is, This camera has a storage capacity of = 256 x1024 x 1024 bytes. Since a single photograph consisted of 1024 pixels per row and 1024 pixels per column, then The number of pixels in one photograph is 1024 x 1024 . Since each pixel required three bytes of storage. Thus , A single photograph require the storage of = 1024 x 1024 x 3 bytes Now, The number of photographs could be stored in the camera = ( storage capacity of digital camera) / (storage required by single photograph) The number of photographs could be stored in the camera =

1024 x 1024 x 3 = 3,145,728 bytes per photo => 3,145,728/ 1,000,000 = 3.15 MB per photo => 256 / 3.15 = 81.26 => 81 photos per camera.

Answer 2

This isn't an easy question to answer because of the way compression works.

The simplest answer is, a square image 1024 x 1024 has one megabyte's worth of pixels, so therefore a 256MB storage space will hold 256 of them. If these were grayscale photos (which have only one channel), that works. Most photos are color, which have three channels, so you could keep 85 photos in that space.

If your camera saves in JPEG format, the camera will save photos to different sizes depending on what's in them - a black cat against a black car will produce a smaller file than a flower garden, because there are more color transitions in the flower garden.