yellow and white and i mean urine
The pI of Isoleucine is 5.98
A pi equals 3.1415326535897932384626433832795028841971693993751058209749445923
The additive primary colors, or primary colors of light, are red, green and blue. The subtractive primary colors, or primary colors of paint, are red, yellow, and blue The primary colors of printing are magenta, cyan, and yellow. thanx bye
Pi is infinite and has no end.
proportions of yellow , red , and blue
Assuming the shape concerned is a circle, Radius = Circumference/(2*pi)and thenArea = pi*(radius)2= pi*(circumference)2/(2*pi)2= (circumference)2/(4*pi)Assuming the shape concerned is a circle, Radius = Circumference/(2*pi)and thenArea = pi*(radius)2= pi*(circumference)2/(2*pi)2= (circumference)2/(4*pi)Assuming the shape concerned is a circle, Radius = Circumference/(2*pi)and thenArea = pi*(radius)2= pi*(circumference)2/(2*pi)2= (circumference)2/(4*pi)Assuming the shape concerned is a circle, Radius = Circumference/(2*pi)and thenArea = pi*(radius)2= pi*(circumference)2/(2*pi)2= (circumference)2/(4*pi)
2 pi / 2 = pi.
To find an angle that is coterminal with ( \frac{3\pi}{2} ), you can add or subtract multiples of ( 2\pi ). For example, ( \frac{3\pi}{2} + 2\pi = \frac{3\pi}{2} + \frac{4\pi}{2} = \frac{7\pi}{2} ) is coterminal with ( \frac{3\pi}{2} ). Similarly, subtracting ( 2\pi ) gives ( \frac{3\pi}{2} - 2\pi = \frac{3\pi}{2} - \frac{4\pi}{2} = -\frac{\pi}{2} ), which is also coterminal.
No. It is circumference/(2*pi)No. It is circumference/(2*pi)No. It is circumference/(2*pi)No. It is circumference/(2*pi)
C = 2 pi R = 9.42 R = 9.42 / (2 pi) A = pi R2 = pi [ 9.42 / (2 pi) ]2 = (9.42)2 pi / 4 pi2 = (9.42)2 / (4 pi) = 7.0614 (rounded) ======================================== I just thought of something: C = 2 pi R A = pi R2 = 1/2 (2 pi R) x (R) = 1/2 (2 pi R) x (1/2pi) (2 pi R) = C/2 x C/(2 pi) = C2 / (4 pi)Let's see if this gives the same answer as above: C2 / (4 pi) = (9.42)2 / (4 pi) = 7.0614 Yay ! Next time, I'll remember that the area is (circumference2) divided by (4 pi).
11pi/12 = pi - pi/12 cos(11pi/12) = cos(pi - pi/12) cos(a-b) = cos(a)cos(b)+sin(a)sin(b) cos(pi -pi/12) = cos(pi)cos(pi/12) + sin(pi)sin(pi/12) sin(pi)=0 cos(pi)=-1 Therefore, cos(pi -pi/12) = -cos(pi/12) pi/12=pi/3 -pi/4 cos(pi/12) = cos(pi/3 - pi/4) = cos(pi/3)cos(pi/4)+sin(pi/3) sin(pi/4) cos(pi/3)=1/2 sin(pi/3)=sqrt(3)/2 cos(pi/4)= sqrt(2)/2 sin(pi/4) = sqrt(2)/2 cos(pi/3)cos(pi/4)+sin(pi/3) sin(pi/4) = (1/2)(sqrt(2)/2 ) + (sqrt(3)/2)( sqrt(2)/2) = sqrt(2)/4 + sqrt(6) /4 = [sqrt(2)+sqrt(6)] /4 Therefore, cos(pi/12) = (sqrt(2)+sqrt(6))/4 -cos(pi/12) = -(sqrt(2)+sqrt(6))/4 cos(11pi/12) = -(sqrt(2)+sqrt(6))/4
Do you mean Sin(pi/2) = 1 or [Sin(pi)] /2 = 0.0274....
Circumference = 2 pi R = 33R = 33 / (2 pi)Area = pi R2 = pi (33)2 / (2 pi)2= (33)2 / (4 pi) = 86.66 square units
S = 2 pi r h + 2 pi r2S - 2 pi r2 = 2 pi r hh = (S - 2 pi r2) / (2 pi r)
(pi/2)-1 = 2/pi
No, since Pi is an irrational number, 2(pi) would still be irrational.
all multiples of pi. pi, 2 pi, - pi, -2 pi and so on...