yellow and white and i mean urine
The additive primary colors, or primary colors of light, are red, green and blue. The subtractive primary colors, or primary colors of paint, are red, yellow, and blue The primary colors of printing are magenta, cyan, and yellow. thanx bye
A pi equals 3.1415326535897932384626433832795028841971693993751058209749445923
The pI of Isoleucine is 5.98
proportions of yellow , red , and blue
Pi is infinite and has no end.
Assuming the shape concerned is a circle, Radius = Circumference/(2*pi)and thenArea = pi*(radius)2= pi*(circumference)2/(2*pi)2= (circumference)2/(4*pi)Assuming the shape concerned is a circle, Radius = Circumference/(2*pi)and thenArea = pi*(radius)2= pi*(circumference)2/(2*pi)2= (circumference)2/(4*pi)Assuming the shape concerned is a circle, Radius = Circumference/(2*pi)and thenArea = pi*(radius)2= pi*(circumference)2/(2*pi)2= (circumference)2/(4*pi)Assuming the shape concerned is a circle, Radius = Circumference/(2*pi)and thenArea = pi*(radius)2= pi*(circumference)2/(2*pi)2= (circumference)2/(4*pi)
2 pi / 2 = pi.
No. It is circumference/(2*pi)No. It is circumference/(2*pi)No. It is circumference/(2*pi)No. It is circumference/(2*pi)
C = 2 pi R = 9.42 R = 9.42 / (2 pi) A = pi R2 = pi [ 9.42 / (2 pi) ]2 = (9.42)2 pi / 4 pi2 = (9.42)2 / (4 pi) = 7.0614 (rounded) ======================================== I just thought of something: C = 2 pi R A = pi R2 = 1/2 (2 pi R) x (R) = 1/2 (2 pi R) x (1/2pi) (2 pi R) = C/2 x C/(2 pi) = C2 / (4 pi)Let's see if this gives the same answer as above: C2 / (4 pi) = (9.42)2 / (4 pi) = 7.0614 Yay ! Next time, I'll remember that the area is (circumference2) divided by (4 pi).
11pi/12 = pi - pi/12 cos(11pi/12) = cos(pi - pi/12) cos(a-b) = cos(a)cos(b)+sin(a)sin(b) cos(pi -pi/12) = cos(pi)cos(pi/12) + sin(pi)sin(pi/12) sin(pi)=0 cos(pi)=-1 Therefore, cos(pi -pi/12) = -cos(pi/12) pi/12=pi/3 -pi/4 cos(pi/12) = cos(pi/3 - pi/4) = cos(pi/3)cos(pi/4)+sin(pi/3) sin(pi/4) cos(pi/3)=1/2 sin(pi/3)=sqrt(3)/2 cos(pi/4)= sqrt(2)/2 sin(pi/4) = sqrt(2)/2 cos(pi/3)cos(pi/4)+sin(pi/3) sin(pi/4) = (1/2)(sqrt(2)/2 ) + (sqrt(3)/2)( sqrt(2)/2) = sqrt(2)/4 + sqrt(6) /4 = [sqrt(2)+sqrt(6)] /4 Therefore, cos(pi/12) = (sqrt(2)+sqrt(6))/4 -cos(pi/12) = -(sqrt(2)+sqrt(6))/4 cos(11pi/12) = -(sqrt(2)+sqrt(6))/4
The circumference of a circle: C = 2(pi)r The area of a circle: A = (pi) r^2 C = 25.12 cm 2(pi)r = 25.12 cm r = 25.12/[2(pi)] r = 12.56/pi r^2 = 157.7536/pi^2 So, A = (pi)r^2 A = (pi)(157.7536/pi^2) A = 157.7536/pi A = 50.22 cm^2 (approximately)
S = 2 pi r h + 2 pi r2S - 2 pi r2 = 2 pi r hh = (S - 2 pi r2) / (2 pi r)
Circumference = 2 pi R = 33R = 33 / (2 pi)Area = pi R2 = pi (33)2 / (2 pi)2= (33)2 / (4 pi) = 86.66 square units
No it is 2*radius*pi or diameter*pi or 2(pi)r
(pi/2)-1 = 2/pi
This has an infinite number of answers, for example: pi / 1, (2 x pi) / 2, 1 / (1/pi), etc.This has an infinite number of answers, for example: pi / 1, (2 x pi) / 2, 1 / (1/pi), etc.This has an infinite number of answers, for example: pi / 1, (2 x pi) / 2, 1 / (1/pi), etc.This has an infinite number of answers, for example: pi / 1, (2 x pi) / 2, 1 / (1/pi), etc.
No, since Pi is an irrational number, 2(pi) would still be irrational.