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Can someone please help me out.....balance K plus H2SO4 arrow K2SO4 plus H2?
The balanced chemical equation for the reaction between potassium (K) and sulfuric acid (H2SO4) to form potassium sulfate (K2SO4) and hydrogen gas (H2) is: 2K + H2SO4 -> K2SO4 + H2
How do you balance the equation K plus H2O yields H2 plus KOH?
Balanced :2 K + 2 H2O ----> 2 KOH + H2
How do you balance FeCl2 H2?
To balance the equation FeCl2 + H2 = Fe + HCl, you need to add coefficients. Start by balancing the iron atoms on both sides, then balance the chlorine atoms, and finally balance the hydrogen atoms. The balanced equation is FeCl2 + H2 = Fe + 2HCl.
Balance the equation1.H2+ O2=H2O?
= H2+O2 =2H2+O2=2H2O
How do you balance K plus H20---KOH plus H2?
This is a chemical equation representing the reaction of potassium with water to form potassium hydroxide and hydrogen gas: 2K + 2H₂O → 2KOH + H₂. To balance it, simply ensure that the number of atoms of each element is the same on both sides of the equation. In this case, the equation is already balanced.
How do you balance AL CI H2?
It is impossible to balance AL CI H2 because it is an incomplete equation. There are products missing from this chemical equation. If your query was how do you balance 2 HCI + 2AL then the answer would be 2 HC1 + 2 AL = 2 ALCI + H2.
What is the balance of K Br2 2KBr?
You need to have values for K, Br2 and 2KBr in order to find out the balance. For example, if you had the values as H2 + O2 = H20 the balanced chemical equation would be 10 H2 = H20.
How do you balance this equation Na plus H2O to H2 plus NaOH?
2Na + 2H2O -> H2 + 2NaOH
Balance equation when mercury reacts with hydrochloric acid?
The balanced chemical equation for the reaction of mercury (Hg) with hydrochloric acid (HCl) is: Hg + 2HCl -> HgCl2 + H2
How do you balance this equation Na plus H2O equal to NaOH plus H2?
2Na + 2H2O -------> 2NaOH + H2
ANSWERED How many g of potassium must react with H20 to produce 1.60 L of H2 at STP according to the following equation?
Given the reaction 2K + 2H2O -> 2KOH + H2, we can see that 2 moles of potassium react to produce 1 mole of hydrogen gas. At STP, 1 mole of any gas occupies 22.4 L. Therefore, for 1.6 L of hydrogen gas, 2 moles of potassium are needed, which is approximately 155 g of potassium.
What would happen to the rate of a reaction with rate law rate k NO 2 H2 if the concentration of H2 were halved?
Halving the concentration of H2 will decrease the rate of the reaction, assuming it is a first-order reaction with respect to H2. Since the rate law is rate = k[NO]^2[H2], cutting the concentration of H2 in half will decrease the rate of the reaction by a factor of 0.5.
