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By using one of the simple equations of motion.

s = ut + 1/2 at2

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Q: How do you calculate the displacement of an object when the object's initial velocity constant acceleration and time of travel are known?
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What happens to the displacement velocity and acceleration of an object as it falls through the air to the ground?

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this my sound rather daft but this is a bit of a trick question, the speed is the same so straight away you would think the acceleration is constant right....???? Wrong the displacement of the object is changing (displacement is the distance being travelled with a direction, a vector quantity.) as the displacement is changing so is the velocity, as velocity is displacement/time. as the velocity is changing so is the acceleration because acceleration is then change in velocity divided by time.


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