Is it y=18-2x?
If so,
when solving x-intercept, y=0
y=18-2x
18-2x=y
18-2x=0
-2x=-18
-2x/-2=-18/-2
x=9
so, x intercept is 9
when solving y-intercept, x=0
y=18-2x
18-2x=y
18-2(0)=y
y=-12
so, y intercept is -12
In the equation y = f(x), Put x = 0 and solve for y. Those are the y intercepts. Put y = 0 and solve for x. Those are the x intercepts.
I believe that you need an equation to solve for the x and y intercepts.
The x coordinate for all y intercepts is 0, just as the y coordinate for all x intercepts is 0.
Oh, finding the x and y intercepts is like finding little treasures in your painting. To find the x-intercept, you set y to zero and solve for x. To find the y-intercept, you set x to zero and solve for y. Remember, there are no mistakes in mathematics, just happy little accidents.
Factoring a quadratic allows you to solve the x and y intercepts. The x-intercepts in the factored form are the inverse of the constants. The y-intercept is the product of the x-intercepts multipied together. Example: x²-10x-24 = (x+2)(x-12) +2 and -12 are the constants. So ur x-intercepts are (-2,0) (12,0). The y intercept is -24 because -2 X 12 = -24.
To solve for intercepts on a straight line graph put the equation in the form y=mx+c where c is the y-intercept and you have the y intercept. Now to solve x-intercept set y=0 eg y=2x+5 0=2x+5 2x=-5 x=-2.5 For intercepts on other forms of graphs eg parabola y-intercept= make x equal to 0 and solve x-intercept= make y equal to 0 and solve
The x and y intercepts are where a line on a graph intersects (crosses over) the x or y axis.
18
Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
To find the intercepts of the equation (y = x^4 - 2x^2 - 8), we need to determine where the graph intersects the x-axis and y-axis. For the y-intercept, set (x = 0), yielding (y = -8), so the y-intercept is (0, -8). To find the x-intercepts, set (y = 0) and solve the equation (x^4 - 2x^2 - 8 = 0); this can be factored or solved using substitution methods, leading to the x-intercepts at approximately (x \approx 2.414) and (x \approx -2.414).
To find the y-intercept you substitute in 0 for x and solve. To find the x- intercept you substitute in 0 for y and solve. If you do it correctly you should find the x-intercept to be -3 and the y-intercept to be 3.
the x is dependent and the y is independent and the x numbers cant repeat themself and yes they do have intercepts