To calculate the time it takes for the feather to hit the ground, we can use the formula for free fall: ( d = \frac{1}{2} g t^2 ), where ( d ) is the distance (1.25 m), ( g ) is the acceleration due to gravity (1.62 m/s²), and ( t ) is the time in seconds. Rearranging the formula gives ( t = \sqrt{\frac{2d}{g}} ). Substituting the values, we find ( t = \sqrt{\frac{2 \times 1.25}{1.62}} \approx 1.217 ) seconds.
The time it takes for the feather to hit the surface can be calculated using the equation ( t = \sqrt{\frac{2d}{g}} ), where ( t ) is the time, ( d ) is the initial drop height (1.2m), and ( g ) is the acceleration due to gravity on the moon (1.62 m/s²). Plugging in the values, we get ( t = \sqrt{\frac{2 \times 1.2}{1.62}} \approx 0.77s). So, it takes approximately 0.77 seconds for the feather to hit the surface of the moon.
The force of gravity on the earth is 9.8 m/s^2
Apollo 15 astronaut Dave Scott dropped the hammer and feather to show that since there is no air friction on the moon, and the acceleration of an object by gravity does not depend on the mass of the object.The above experiment is supposed to prove the equivalence principle which states that the acceleration an object feels due to gravity does not depend on its mass, density, composition, colour or shape."Both will hit the moon at the same time?"Answer:If you drop a hammer and a feather from the same height on earth, the hammer will hit the ground first as the feather is slowed down drastically by air resistance.But on the moon, because it is a vacuum, and since the acceleration of an object is the same as the gravity i.e. a = g and the mass is not in the equation, all objects will have the same acceleration and hence the hammer should fall to the surface of moon at the same time as the feather but:"Both will hit the moon at the same time as believed by most scientists?"This may not be absolutely true since every object has its own gravity which is greater if its mass is greater. So the hammer has a gravity much greater than that of the feather. Therefore the combined gravity of the hammer and that of the moon (which pulls the hammer and moon towards each other) is greater than that of the feather and the moon.As such the hammer should collide with the moon marginally earlier than that between the feather and the moon, though this difference is so minute that we assume that the collisions occur simultaneously.However, if the hammer and feather are dropped together, then as the hammer's gravity pulls the moon towards itself, it also pull the moon towards the feather and as such the lucky feather may get a free ride and hits the moon at the same time as the hammer.To be fair, the experiment should be done dropping the objects individually e.g. feather first, then the hammer and then see whether the times taken are the same or not.All the above are valid only on the assumption that the centre of gravity is the part that hits the moon but since this is not necessarily true, we also have to take into account which part of the hammer or feather is nearest to the moon before the two objects were released (assuming that the centre of gravity of both objects are at the same level on release) !The real answer is that there is not enough data for us to know which will hit the moon first !
The acceleration of gravity on the surface of Mercury, and therefore the weight of any mass located there, is roughly 37.7% of what it is on Earth's surface.
The acceleration of gravity at the surface of Mars is approximately 3.7 m/s2. Earth's acceleration is 9.8 m/s2 on average. The force that gravity would exert on an object is dependent on its mass.
The time it takes for the feather to hit the surface can be calculated using the equation ( t = \sqrt{\frac{2d}{g}} ), where ( t ) is the time, ( d ) is the initial drop height (1.2m), and ( g ) is the acceleration due to gravity on the moon (1.62 m/s²). Plugging in the values, we get ( t = \sqrt{\frac{2 \times 1.2}{1.62}} \approx 0.77s). So, it takes approximately 0.77 seconds for the feather to hit the surface of the moon.
The acceleration of gravity at the surface of Earth is approximately 9.81 meters per second squared.
The acceleration due to Gravity is constant at 32 feet per second per second, if you dropped a feather and a cannon ball in a vacuum they would fall at the same rate and hit the floor at he same time.
88% of what it is here ; so 28.2 feet /sec 2
The acceleration due to gravity near the surface of the Earth is approximately 9.81 m/s^2.
The acceleration of gravity on a planet determines how fast an object will fall when dropped, affecting the weight of objects on the surface. This acceleration also impacts the force needed for objects to stay grounded or lifted from the surface. Overall, gravity's acceleration is essential in understanding an object's behavior on the planet's surface.
The value for acceleration due to gravity on the surface of the Earth is approximately 9.81 m/s^2.
acceleration due to gravity of earth is 9.8ms-2
Yes. The moon's surface gravity is about 1/6 what it is on Earth.
A hammer falls faster than a feather when dropped on Earth because of gravity. Gravity pulls objects with mass towards the Earth at a constant rate of acceleration, regardless of their size or shape. Since the feather has more surface area and air resistance, it falls slower than the hammer, which is more dense and streamlined.
its 13.6
The acceleration due to gravity near the surface of the Earth is approximately 9.81 m/s^2.