In a circular orbit, a satellite is in free fall and moves with a constant speed, which means that the gravitational force acting on it provides the necessary centripetal force for its circular motion. Since the gravitational force is always perpendicular to the satellite's displacement, the work done on the satellite by gravity is zero. Therefore, no net work is done on a satellite in a stable circular orbit around the Earth.
No, the work done by the Earth on the space station is not positive. The gravitational force between the Earth and the space station acts towards the center of the Earth, which is perpendicular to the direction of motion of the space station. Therefore, the work done by the Earth on the space station is zero because the force and displacement are perpendicular to each other.
The work done by the Earth on the space station over one complete orbit is zero because the gravitational force is conservative. This means that the work done in moving an object over any closed path is zero.
The work done by the Earth on the space station is zero since the force of gravity is perpendicular to the motion of the space station. This means that there is no displacement in the direction of the force, and thus no work is done.
Rockets have sent unmanned spacecraft to mars and Jupiter. Satellites put in orbit by rockets beam back information about earth's atmosphere and weather.
Well, I would say YES! It keeps the air on the earth so we can all breath, it keeps the earth from just going off into space away from our source of all our energy, the sun. It keeps us from just floating away into space. There are millions of things gravity does that is positive work. I can not even to begin to name them.
The work done on a satellite in a circular orbit around Earth is zero because the gravitational force acting on the satellite is perpendicular to the direction of motion, so no work is done to maintain the orbit.
In a complete circular orbit of an electron around a nucleus, the work done by the field of the nucleus is zero. This is because the force is always perpendicular to the direction of motion, so there is no displacement along the direction of the force, resulting in no work done. If the orbit is elliptical, there would be work done by the field of the nucleus due to the non-zero component of the force parallel to the direction of motion during the orbital motion.
No, the work done by the Earth on the space station is not positive. The gravitational force between the Earth and the space station acts towards the center of the Earth, which is perpendicular to the direction of motion of the space station. Therefore, the work done by the Earth on the space station is zero because the force and displacement are perpendicular to each other.
The Moon definitely has an effect on the Earth's orbit. It can't "pull the Earth out of orbit" because if it could do so, it would have done so billions of years ago and you wouldn't be here to wonder about it.
Here a centripetal force provided by electrostatic force of attraction acts on the electron towards the centre of orbit but motion is along the tangent to the circular orbit at ecah point. As force and displacement are in mutually perpendicular directions at each point, the work done is zero. E V SHAKKEER HUSSAIN
Not very much, I would say. There is no work being done in this situation so there's no change in kinetic energy. So the satellite's speed remains constant. But we already knew the speed was constant. Perhaps I'm missing something.
No because it stays in orbit and takes pictures of the ever changing earth.
NO. The gravity of Earth, in conjunction with the inertia of the satellite, keeps the satellite revolving around Earth. However, the satellite doesn't get any nearer to the Earth. So, according to the laws of physics, no work is done. (I'm ignoring the fact that satellites sometimes lose height and need to be "boosted" a bit to maintain their orbits. Also, I'm assuming that the satellite's orbit is circular. If the orbit is elliptical the answer is more or less the same, but a bit more complicated.)
The work done by the Earth on the space station over one complete orbit is zero because the gravitational force is conservative. This means that the work done in moving an object over any closed path is zero.
It has to reach escape velocity which on Earth is 11.2 Km per second
Kepler's law says that reducing the size of the orbit by a factor of 2 reduces the duration of the revolution by the square root of 8, which means that a full revolution will be done in 129 days instead of 365. ==================================== Another contributor concurred: Bravo. Before I saw this answer, I came up with 129.128 days, assuming that both the initial and final orbits were circular.
The work done by the Earth on the space station is zero since the force of gravity is perpendicular to the motion of the space station. This means that there is no displacement in the direction of the force, and thus no work is done.