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What is length of 2nd pendulum on moon?
The length of a pendulum that has a period of 2 seconds is approximately 0.25 meters on Earth. On the moon, where gravity is about 1/6th of Earth's gravity, the length of a 2-second pendulum would be about 0.73 meters.
If i had a pendulum clock a meter stick and a stopwatch could I find the acceleration of gravity on the moon?
The time it takes a pendulum to complete a full swing is given by the formula: T = 2 pi sqrt(L/g) where L is the length of the pendulum, and g is acceleration due to gravity. With a little algebra we can rearrange this to get: g = (2 pi / T)^2 L So measure the length of your pendulum to get L, then measure how long it takes for a complete swing, plug it into the formula, and there's your acceleration due to gravity. You can try it here on Earth and see what you get.
How much of the moon can you see if it's a full moon?
A whole moon it's that simple
Have space shuttles and current rockets taken humans as far as the moon in recent years?
A Space Shuttle has never taken a human to the moon.
Does a clock work accurately on the moon?
A clock would work accurately on the moon as long as it's designed to account for the different gravitational conditions. The lack of atmosphere and lower gravity on the moon may cause slight variations, but a specially designed clock would be able to accurately keep time.
Time period of simple pendulum is three seconds the same pendulum taken at the moon - what will be its new time period?
This pendulum, which is 2.24m in length, would have a period of 7.36 seconds on the moon.
How would the period of a simple pendulum be affected if it were located on the moon instead of the earth?
The period of a simple pendulum would be longer on the moon compared to the Earth. This is because the acceleration due to gravity is weaker on the moon, resulting in slower oscillations of the pendulum.
What effect does the acceleration due to gravity on the moon have on a simple pendulum?
The lower acceleration due to gravity on the moon causes a simple pendulum to swing more slowly compared to Earth. The period of the pendulum is longer on the moon because gravity plays a role in determining the speed at which the pendulum swings back and forth.
Is a pendulum's time period increases or decreases when it taken from earth to moon?
Increases.
Can you use simple pendulum in moon?
Yes. The period of the pendulum (the time it takes it swing back and forth once) depends on the length of the pendulum, and also on how strong gravity is. The moon is much smaller and less massive than the earth, and as a result, gravity is considerably weaker. This would make the period of a pendulum longer on the moon than the period of the same pendulum would be on earth.
How would the time period of a simple pendulum clock be affected if it were on the moon instead of the earth?
The time period of a pendulum would increases it the pendulum were on the moon instead of the earth. The period of a simple pendulum is equal to 2*pi*√(L/g), where g is acceleration due to gravity. As gravity decreases, g decreases. Since the value of g would be smaller on the moon, the period of the pendulum would increase. The value of g on Earth is 9.8 m/s2, whereas the value of g on the moon is 1.624 m/s2. This makes the period of a pendulum on the moon about 2.47 times longer than the period would be on Earth.
What is the difference in period for a pendulum on earth and a pendulum on moon?
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).
What would the effect be on the period of the simple pendulum if the pendulum was moved from sea level to the top of a mountain or to the moon or to the sun?
As the force of gravity increases the period would decrease. So shortest period on the sun (if you can keep it intact), then sea level, then mountain top and then moon.
If a simple pendulum with a period of 1 second is set in motion of the moon what is the new period of this pendulum?
The equation is: http://hyperphysics.phy-astr.gsu.edu/HBASE/imgmec/pend.gif T is the period in seconds, L is pendulum length in cm, g is acceleration of gravity in m/s2. We know on earth the period is 1s when the acceleration of gravity is 9.8m/s2, so the pendulum length is 24.824cm. The acceleration of gravity on the moon is 1.6m/s2. Substitute 24.824cm for L and 1.6 for g and you yield 2.475 seconds. The period is 2.475 seconds.
How would the period of a simple Pendulum be charged if the pendulum were moved from sea level to the moon?
The period is not likely to be charged. However, it would change due to the weaker gravitational force on the moon. Since the surface gravity of the moon is 0.165 that of the earth, the period would increase by a multiple of 1/sqrt(0.165) = 2.462 approx.
What would happen if a pendulum were to swing on the moon?
If a pendulum were to swing on the moon, it would swing more slowly and for a longer period of time compared to on Earth due to the moon's lower gravity. This is because gravity affects the speed and duration of the pendulum's swing.
Will a pendulum swing on the moon?
I think it will as it has mechanical parts to make the pendulum move, not 100% sure.
