Yes he is
value of acceleration due to gravity is maximum at the surface of earth. So the gravitational field strength. as g'=g(1-d/R) at surface d=R so d=R so g'=g at earth's centre g=0. Its value decrease with decrease or increase in height. as: g'=g(1-2h/R) ......for height h and g'=g(1-d/R) .....for depth d
The formula to calculate the acceleration due to gravity at a certain altitude h above Earth's surface is g' = g * (R / (R + h))^2, where g is the acceleration due to gravity at the Earth's surface (approximately 9.81 m/s^2), R is the radius of the Earth (approximately 6371 km), and h is the altitude. In this case, h = 1.47 * R, so substituting the values into the formula gives g' = 5.64 m/s^2.
According to newtons formula; force F=G*m1*m2/(r^2) ,for 2 bodies facing each others gravitational pull When divided both sides by m1,so gravitational acceleration g=m2*g/(r^2) so g is directly proportional to mass of the body....
It greatly depends upon their distance to one another at the time. However, the universal law of gravitational attraction applies: F = G * ((m1*m2)/r) where m1 is the mass of moon 1 (kg) m2 is the mass of moon 2 (kg) r is the distance (m) G is the gravitational constant F is the force of attraction.
F= G (m1m2)/(r2) F= the gravitational force G= gravitational constant m1= mass of the first object (the satellite) m2= mass of the second object (earth) r= the radius Plug in the values and solve for r: 690 N= 6.67 X 10-11 ((124kg) X (5.98 X 1024)/(r2) 690r2= 6.67 X10-11 (7.41 X 1026) 690r2= 4.94 X 1016 r2= (4.94 X 1016)/(690) r= square root of (7.16 x 1013) r= 8.46 x 106 m, or 846,000 Km
R. G. Armstrong was born on April 7, 1917.
R. G. Armstrong was born on April 7, 1917.
R. G. Armstrong was 95 years old when he died on July 27, 2012. (birthdate: April 7, 1917).
No one knows because they wernt with him that are still alive. And well r u him.
yes
yes
yes.
Yes he is.
Yes
Still alive
R.L. Stine, the author of the Goosebumps series, is still alive.
no i think he died in 1988