A 198-pound man on the Moon would weigh significantly less due to the Moon's weaker gravitational pull, which is about one-sixth that of Earth's. As a result, his weight would be approximately 33 pounds on the Moon. This reduction in weight allows for easier movement and jumping, making activities on the lunar surface quite different from those on Earth.
If he weighs 198 pounds and he goles to the moon he'll weigh 33 pounds cause u divide By six cause u weigh 1/6 less cause there is no gravity so any number u always
301 pounds.
The weight would be approx a sixth and so it would be 661.3 pound-weight.
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A 4000 pound truck would weigh approximately 666.67 pounds on the moon, because the moon's gravity is about 1/6th that of Earth's.
If he weighs 198 pounds and he goles to the moon he'll weigh 33 pounds cause u divide By six cause u weigh 1/6 less cause there is no gravity so any number u always
first u divide and then u do it by multiplying then u eat ....I do not know the answer sorry I'm just like u trying to find the answer yours treasury, ?
301 pounds.
wouldn't it be like 4.4 * c = 198
The weight would be approx a sixth and so it would be 661.3 pound-weight.
20 pound's 20 pound's 20 pound's 20 pound's 20 pound's 20 pound's
One pound of weight on Earth is equivalent to 1/6 pound of Moon-weight, or about 2 and 2/3 ounces.
1/6th of their normal weight on earth. A 180 pound man would weigh 30 pounds.
There are 453.59237 grams in one pound. Therefore to get amount of pounds in grams, value in grams has to be divided by amount of grams in one pound: 198 grams = [grams] / 453.59237 = 198 / 453.59237 = 0.4365 pounds
Man in the Moon = mmoaonn
A 200 pound man weighs more.
198 pounds = 89.811 kilograms or 89 kilograms 811.289 grams1 pound ~= 0.45359 kilograms1 kilogram ~= 2.2046 poundsAlgebraic Steps / Dimensional Analysis Formula 198 lb*1 kg2.2046 lb=89.81128926 kg198 pounds = 89.8112893 kilograms You can solve problems like this using Google. For example, to get the above result, I just Googled: "198 pounds in kg" and I got the result above.