Answer is 3.1*10^7 seconds in a year
How does a planet's distance from the sun affect its period of revolution?
Depending on the number of leap years in the period (14 or 15), there will be 1893369600 or 1893456000 seconds - plus any leap seconds which may be added.
The Earths sidereal rotation period is 23 hours and 56 seconds. = =
The farther it is from the sun the longer its period of revolution (its "year").
2555
The earth rotates 360 degrees every 23 hours, 56 minutes and 4.100352 seconds.
The average momentum of a runner can be calculated by dividing the mass (in kg) of the runner by the time taken to cover the distance (in seconds). This gives the average momentum of the runner during that time period.
To find the average speed from 4 seconds to 8 seconds, you need the total distance traveled during that time interval and the total time taken. The average speed is calculated by dividing the total distance by the total time (4 seconds in this case). If you provide the distance traveled during that period, I can help you calculate the average speed.
The year.
27
27
Period = 1/78.6 seconds = 0.01272 seconds
500 metres is 0.31 miles: whether that distance is covered in a nanosecond or over a period of years.
The SI unit for period is seconds and the symbol is t (because the period is a time measurement, it is expressed in the SI unit seconds)
The frequency is the reciprocal of the period. In other words, divide 1 by the period. If the period is in seconds, the frequency is in hertz.
None. 2.5 seconds is a period of time. It is not a speed since there is no measure of distance involved. By contrast, yards per minte is a measure of speed. The two measures are incompatible.
The period of a wave can be calculated as the inverse of its frequency. In this case, the period would be 1/250 seconds, which is equal to 0.004 seconds.