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Strictly speaking, it does not. However, the moon does have a greater influence on the tides. Tides are not simply the result of the Moon's gravity. Rather, they occur because the strength of gravity decreases with distance, which means that the moon exerts a stronger gravitational pull on the water on the side facing it than it does at the average point on Earth. Such effects are called tidal forces.

Gravity from an object is directly proportional to its mass and inversely proportional to the square of the distance. This means if you double the mass you double the gravity. If you double the distance, gravity is reduce to 1/4 the original value. If yo triple your distance, gravity is reduced to 1/9 and so on.

Tidal forces are also directly proportional to mass but are inversely proportional to the cube of the distance, so if you double your distance you reduce tidal forces to 1/8. If you triple the distance, you reduce them to 1/27.

So let's do the math. The sun is about 27 million (27,000,000) times the mass of the moon and about 390 times farther away from Earth than the moon is.

First, to calculate the ratio of gravitational force:

27,000,000/(390^2) ≈ 27,000,000/152000 ≈ 178.

So the sun's gravity exerts nearly 180 times more force on Earth than the moon's gravity does.

However if we calculate the ratio of tidal forces

27,000,000/(390^3) ≈ 27,000,000/59,300,000 ≈ 0.455.

So the moon's tidal forces on the Earth are a little more than twice those exerted by the sun.

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9y ago

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