Pulsar
Quasar
Radial(?)
These are all names for some variety of "star"
Emma S. Bellows is a person whose initials are ESB. Her husband, George Wesley Bellows was an artist. When he died, many of his lithographs and drawings were unsigned. Emma signed them with his name, then added her initials.
A-S-T-R-O-N-A-U-T. Astronaut.
R = 2S(R) - 3 = 3 (s - 3)(2S) - 3 = 3s - 9-3 = s - 9S = 6R = 12
I know you have Dr. Glatzer M A R S
Tangential velocity squared is GMs/r and velocity v =29814m/s and the centripetal acceleration is v2/r= 5.928 E-3 m/s2
"What is the answer to this riddle you live above a star but do not burn i have eleven neighbours but they never turn My initials are pq and r and sometimes s What are you?" Take a look on your mobile phone keypad, in particular the number 7 ;-)
m = pqr/s Multiply both sides by s: ms = pqr Divide both sides by pq: ms/pq = r
If PQ and RS are two 2-digit numbers, then PQ * RS = 100*P*R + 10*P*S + 10*Q*R + Q*S
The number 7 on a phone dial pad.
== A n s w e r ==None.
R. L. S. (Robert Louis Stevenson) R. L. B. S. (Robert Louis Balfour Stevenson)
Suppose x and y are two rational number.Then x = p/q and y = r/s where p, q, r and s are integers, with q and s being non-zero. Then x - y = p/q - r/s = pq/qs - qr/qs = (pq - rs)/qs. The signs of x and y do not matter, in so far as their signs will be used to determine the signs of p,q, r and s.
You do it the obvious way. Take p, q in Q, the rationals By definition, we can write p = m/n and q = r/s where m, r are integers, n and s are natural. we define pq (p times q) = (mr)/(ns) p/q = pq^-1 where q^-1 denotes q's multiplicative inverse s/r Remark: you cannot divide by 0 here because 1) 0 have no multiplicative inverse 2) if r = 0. s/r is undefined.
The number 7 on your phone keypad
It is most probably Sleigh Ride.
The number 7 on a telephone key pad.
i have the same question...