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What else can I help you with?
Will the m-audio fast track pro work with windows 8?
Not currently.
Will M-audio fast track ultra work with pro tools m-powered 7.1?
It should work, but check the manual just in case.
How many joules of work are done on a box when a force of 25 N pushes it 3 m?
The work done on the box can be calculated using the formula: Work = Force x Distance. Therefore, the work done on the box is 75 Joules (25 N x 3 m).
What is the recommended PC specification for running pro tools le on an m box 2 usb system?
See the manual.
Is a m and m an acid or a base?
A acid
Do you need an external sound card for pro tools LE 8.0?
Yes, you need an M-box 2, 002 or 003.
Does pro tools le 7.0 need m box to use it?
Yes only protools 9 doesnt need an mbox.
A force of 300 N is applied to a box for 10 seconds in order to move the box 10 m. What is the power?
The work done on the box is 3000 Joules (N*m) (300 N * 10 m). Power is work done per unit time, so the power applied to the box is 300 Watts (3000J / 10 s).
If you want to lift a 30 kg box to a height of 1 m how much work will it take?
The work done to lift the box to a height of 1 m can be calculated using the formula: work = force x distance. In this case, the force required to lift the box against gravity is equal to its weight, which is 30 kg * 9.8 m/s^2 (acceleration due to gravity). The distance is 1 m. Therefore, the work done is 294 joules.
If you want to lift a 30kg box to a height pf 1 m how much work will it take?
To calculate the work required to lift the box, you can use the formula: work = force × distance. In this case, the force is equal to the weight of the box (30 kg * 9.8 m/s^2) and the distance is 1 meter. So the work required would be 294 joules.
How much work have you done if you pushed with a force of 18 N on a box while sliding it 3.4 m is the answer 61 N-m?
Yes. The amount of work would be 61N•m, or 61 Joules.
If a force 10.0 n is used to lift a box a distance of 0.9 m how much work is done?
The work done to lift the box is given by the formula: work = force x distance. Plugging in the values with force = 10.0 N and distance = 0.9 m, the work done would be 9.0 Joules.
