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How many volts will it take to make 12 amps go through 3 ohms of resistance?
Use Ohm's Law: V = IR (voltage = current times resistance).
How many amps in 120volts and 500ohms?
You use Ohm's Law to make your calculation. Volts = Amps x Resistance Amps = Volts / Resistance
How much voltage is required to make 2 amperes flow through resistance of 8 ohms?
Ohm's Law: voltage is current times resistance, so 8 amps times 2 ohms is 16 volts.
How much voltage is used to measure resistance?
The voltage needed to make a resistance measurement varies in proportion to the Ohms value being measured. Resistance measurements in the order of thousands and up to one Megohm are low enough to be made with a 1.5 volt or similar cell. However, resistance measurements in the order of hundreds to thousands of Megohm will require a higher voltage of up to 500 Volts DC. A Megger is a device that uses hundreds of volts to make resistance measurements.
How does a 10 watts bulb work in a series connection?
A 10 watt bulb is defined by the voltage supply and the resulting current. So to make the math simple, suppose you have a 10 watt incandescent bulb designed to work at 20 volts. That means it will draw 1/2 amps. Watts = Volts x Amps. The resistance of the bulb is then Volts / Amps so in this case the resistance of the bulb would be 40 ohms. So our mythical bulb has a resistance of 40 ohms with 20 volts across the bulb in our example. Now if we put two of these bulbs in series with the same 20 volts we now have a total resistance of 80 ohms supplied by 20 volts and the circuit will draw 1/4 amp. This lower current will cause the bulbs to be dimmer.
I want to convert 12 volts DC to 29.5 volts DC by using a 400 watt power inverter will it work?
In short, no. There are ways to make the voltage rise, but inverting the power will not help you. If you don't care about the amount of Amps you have, the simplest way to raise the voltage would be to add resistance to the line. Volts and amps are linked by Ohm's law, which states that V=IR, where V is volts, I is current (in amps), and R is resistance in ohms. Therefore you can create a higher voltage at the cost of amperage by adding resistance to your line.
How could two circuits have the same current but different resistances?
The equation, I=V/R (Current = Voltage/Resistance) determines the current, so if you increase both V and R, you will be able to get the same current (with a bit of adjustment to make it exact)example:10 Volts & 2 Ohms resistance = 5 Amps Current20 Volts & 4 Ohms resistance = 5 Amps Current
How much current is need for 12 VDC to flow through water?
First thing voltage does not flow current does. Voltage is the potential or pressure needed to make the current flow. Current is directly proportional to the applied voltage and inversely proportional to the resistance of the circuit. To make the current flow you have to adjust the resistance of the circuit and that would be the water in this case. Salt added to water will make the water conductive so the resistance can be adjusted thereby making the current rise or fall depending on the water solution's resistive properties. The equation that you should consider using is Amps = Volts/Resistance.
How many watts make a volt?
Watts are a unit of power and Volts are a unit of electric potential, so they cannot be directly compared. However, Watts and Volts can be related byWatts = Volts * AmperesorWatts = (Volts^2) / Ohmswhere Amperes are a unit of current and Ohms are a unit of resistance. So, for example, if a lightbulb draws .333 Amps of current at 120 Volts, it is a 40 Watt bulb. (.333 A * 120 V = 40 W)
What is the resistance in a 60W 12 V light bulb?
To produce 60 watts at 120 volts, you need 0.5 amps (Watts = Volts * Amps) At 120volts, a 240ohm resistor would produce 0.5 amps (Amps = Volts / Resistance) A 60 watt bulb will have a resistance of 240 ohms. Note that this is the resistance while the bulb is hot. You might measure a different resistance if you use an ohm meter because the filament is cold.
How much electrical resistance does a big city have?
The resistance is simply the value of resistances of all electrical equipment connected in Parallel by all consumers in a big city.The answer is amazingly accurate, if we have the average power consumption (Megawatts-MW) figure from the power company at any time of the day.Suppose a big city is consuming 100-MW at a given time. Assuming we use 100 volts AC at consumer homes, then at any given moment the instantaneous resistance (R in ohms) of the city is simply given by the formula:Power(watts) = (Volts x Volts) / Resistance (R in ohms)..........or,P=V2/ R, therefore,R = V2/P (ohms)......... then,If:V=100 volts (ac)P= 100,000,000 wattsThen:R = 100 x 100 / 100,000,000 = 0.0001 (ohms)(make sure to use only watts, volts and ohms in the formula above).Good Luck !The resistance is simply the value of resistances of all electrical equipment connected in Parallel by all consumers in a big city.The answer is amazingly accurate, if we have the average power consumption (Megawatts-MW) figure from the power company at any time of the day.Suppose a big city is consuming 100-MW at a given time. Assuming we use 100 volts AC at consumer homes, then at any given moment the instantaneous resistance (R in ohms) of the city is simply given by the formula:Power(watts) = (Volts x Volts) / Resistance (R in ohms)..........or,P=V2/ R, therefore,R = V2/P (ohms)......... then,If:V=100 volts (ac)P= 100,000,000 wattsThen:R = 100 x 100 / 100,000,000 = 0.0001 (ohms)(make sure to use only watts, volts and ohms in the formula above).Good Luck !The resistance is simply the value of resistances of all electrical equipment connected in Parallel by all consumers in a big city.The answer is amazingly accurate, if we have the average power consumption (Megawatts-MW) figure from the power company at any time of the day.Suppose a big city is consuming 100-MW at a given time. Assuming we use 100 volts AC at consumer homes, then at any given moment the instantaneous resistance (R in ohms) of the city is simply given by the formula:Power(watts) = (Volts x Volts) / Resistance (R in ohms)..........or,P=V2/ R, therefore,R = V2/P (ohms)......... then,If:V=100 volts (ac)P= 100,000,000 wattsThen:R = 100 x 100 / 100,000,000 = 0.0001 (ohms)(make sure to use only watts, volts and ohms in the formula above).Good Luck !The resistance is simply the value of resistances of all electrical equipment connected in Parallel by all consumers in a big city.The answer is amazingly accurate, if we have the average power consumption (Megawatts-MW) figure from the power company at any time of the day.Suppose a big city is consuming 100-MW at a given time. Assuming we use 100 volts AC at consumer homes, then at any given moment the instantaneous resistance (R in ohms) of the city is simply given by the formula:Power(watts) = (Volts x Volts) / Resistance (R in ohms)..........or,P=V2/ R, therefore,R = V2/P (ohms)......... then,If:V=100 volts (ac)P= 100,000,000 wattsThen:R = 100 x 100 / 100,000,000 = 0.0001 (ohms)(make sure to use only watts, volts and ohms in the formula above).Good Luck !
If the voltage is 12 volts and the resistance is 3 ohms what are the amps in this circuit?
Oh, dude, it's like basic math here. So, you just divide the voltage by the resistance to get the current. In this case, 12 volts divided by 3 ohms equals 4 amps. So, the current in this circuit would be 4 amps. Easy peasy lemon squeezy!
