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What else can I help you with?
How can you simplify the expression log(log(n))?
To simplify the expression log(log(n)), you can rewrite it as log(n) / log(10).
What is the n power of 2 and get 225?
2n=225 Log 2n=Log 225 (taking logarithm on both sides) n Log 2=Log 225 n=Log 225 / Log 2 n=2.35 / 0.301 n=7.81 (answer rounded to 3 significant figure)
What is the value of n if 2 to the power of n equals 20000?
2ⁿ = 20000 → log(2ⁿ) = log(20000) → n log(2) = log(20000) → n = log(20000)/log(2) You can use logs to any base you like as long as you use the same base for each log → n ≈ 14.29
If log a equals x and log b equals y what is log?
"Log" is not a normal variable, it stands for the logarithm function.log (a.b)=log a+log blog(a/b)=log a-log blog (a)^n= n log a
What is the time complexity of an algorithm that has a running time of n log n?
The time complexity of an algorithm with a running time of n log n is O(n log n), which means the algorithm's performance grows in proportion to n multiplied by the logarithm of n.
If N equals 25.5 what does log N equal?
log N would equal approximately 1.41.
How does the time complexity of an algorithm differ when comparing log(n) versus n?
When comparing the time complexity of an algorithm with log(n) versus n, log(n) grows slower than n. This means that an algorithm with log(n) time complexity will generally be more efficient and faster than an algorithm with n time complexity as the input size increases.
How do you calculate Log2 in Excel?
Use the LOG function. =LOG(n,b) n = Number b = Base =LOG(2,10) = 0.30103
How does the equation 2 raised to the power of log n equal n?
When the equation 2 raised to the power of log n is simplified, it equals n.
Why log 0 is infinite?
the definition of log N = X is 10 to the X power =N for log 0 we have 10 to the x power = 0 The solution for x is that x is very large (infinite) and negative, that is, minus infinity As N gets smaller and smaller, log N approaches minus infinity log 1 = 0 log .1 = -1 log .001 = -3 log .000001 = -6 log 0 = -infinity
What is the fastest integer multiplication algorithm available?
The fastest integer multiplication algorithm available is the SchnhageStrassen algorithm, which has a time complexity of O(n log n log log n).
How can you prove that log n is o(n)?
One way to prove that log n is o(n) is by using the definition of big O notation. In this case, you can show that for all n greater than a certain value, log n is always less than some constant times n. This can be demonstrated through mathematical manipulation and analysis of the growth rates of log n and n.
