Fehling's A and Fehling's B are used together in the Fehling's test to detect the presence of reducing sugars, such as glucose. Fehling's A is a copper(II) sulfate solution, while Fehling's B is a complex solution of potassium sodium tartrate and sodium hydroxide. They work together to oxidize the sugar, causing a color change that indicates the presence of a reducing sugar.
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The Fehling A solution contain copper sulfate.The Fehling B solution contain sodium potassium tartrate and sodium hydroxide.
I think you are referring to the test using Fehlings solution. Fehlings solution oxidises aldehydes and ketones and formic acid and is in turn reduced. The red precipitate is the copper(I) oxide formed by reduction of the copper(II) complex found in Fehlings solution. Acetic acid is not readily oxidised and so there is no precipitate. See link for more information on what the complex is in Fehlings solution and how it is prepared.
When the two Fehling Solutions A and B are mixed, a deep blue solution containing a complex cupric ion is formed. On interaction with reducing compounds such as aldehydes or sugars, the copper is reduced to the univalent stage, and a red, yellow, or yellowish green precipitate is formed.
When Fehling A & B are mixed in equal quantities... Fehlings Reagent is formed which is DEEP BLUE in colour Hope that answers your question! :)
Fehling test is used for reducing sugars.
Fehling's A solution is blue in color due to the presence of copper sulfate.
Fehling's solution is originally blue in color due to the presence of copper ions.
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yes because honey is a monosaccharide All monosaccharides reduce weak oxidizing agents such as Cu2+ in fehlings's reagent.
If both are unknown, you have to keep it as a+b. If they're known, just add them
E B G B- Music Notes Got the E B G B'S and I can keep still EBGB