Yes, fuses have a low resistance in order to not dominate the consumption of the circuit's power, such that the desired appliance wired in series with the fuse consumes the bulk of the power.
Low resistance and low melting point by "justquikr.com"
low resistivity and low melting point.
No, fuse wire is characterized by low resistance and a low melting point. This allows the fuse wire to melt quickly and break the circuit when there is an overload of current, thereby protecting the circuit from damage.
It has high specific resistance and low melting point.........
The resistance of fuse wire is low, typically in the range of 0.01 to 1 ohm. This low resistance allows the fuse wire to quickly heat up and melt when current exceeds a safe level, breaking the circuit and protecting the rest of the circuit from damage.
An amp fuse does not have a specific resistance in ohms. The resistance of a fuse is very low, usually in the milliohm range, and is designed to blow (open) when the current exceeds a certain threshold to protect the circuit.
The fuse needs a low melting point and reletivelyhigh resistance so that it melts at the proper current
Zero. There is no resistance on an open fuse because there is no connection between the terminals on the fuse. I beg to differ There is INFINITE resistance in a BLOWN fuse... There is ZERO resistance in a GOOD fuse.
The material suitable for making a fuse wire should have a low melting pt. so that it can easily melt and cut off the flow of current and save the electrical appliance...
The material for the fuse wire should have low resistance and a low melting point. Ductility is a incidental factor. As the current flow nears the fuse rating, the high current flow causes the wire to heat up quickly. It then melts, opening (breaking) the circuit. This is how the fuse limits the amount of current that can flow through a circuit.
Graphite is low resistance of electricity...
Maybe blow the fuse or burn out the wiring. An ammeter has an extremely low resistance. connecting it across the resistance causes the resulting parallel resistance to be slightly lower than the resistance of the ammeter 1/Rt = 1/R + 1/R(ammeter)