The amount of antifreeze in a radiator typically ranges from 1 to 3 gallons, depending on the make and model of the vehicle. Most radiators hold about 1.5 to 2.5 gallons of coolant, which is usually a mixture of antifreeze and water. It's important to consult the vehicle's owner manual for the specific capacity and recommended coolant mixture.
how many gallons of antifreeze in a 2003 blazer radiator with a/c
That depends on the radiator, not the engine.
The radiator alone, aprox one gallon. The complete cooling system, aprox 15 qts.
The radiator itself probably holds a half gallon. The car as a whole would hold about 2 gallons.
The 1998 Chevrolet Tahoe with a 5.7L engine typically requires about 12 to 14 quarts of coolant for the radiator and engine combined. Since there are 4 quarts in a gallon, this translates to approximately 3 to 3.5 gallons of antifreeze. Always refer to the owner's manual for the most accurate specifications for your vehicle.
For a 2000 Mercury Mountaineer, the cooling system capacity is approximately 16 quarts (or 4 gallons) when including the radiator and engine block. When adding antifreeze, it's generally recommended to use a 50/50 mix of antifreeze and distilled water. Therefore, you would need about 2 gallons of antifreeze and 2 gallons of water to achieve the proper mixture. Always check your owner's manual for specific recommendations.
Cleans antifreeze and dirt out of the radiator
Antifreeze
70 gallons of 20% solution contains 70*0.2 = 14 gallons of antifreeze. Suppose you need G gallons of the 80% antifreeze solution. This will contain 0.8*G gallons of antifreeze. Total volume of solution = G + 70 gallons Volume of antifreeze required in this solutions to make it a 70% solution is 0.7*(G + 70) = 0.7G + 49 gallons. Volume of antifreeze = 14 + 0.8G gallons So 0.7G + 49 = 14 + 0.8G 0.7G + 35 = 0.8G 35 = 0.1G 350 = G Answer: 350 gallons.
330 gallons of 80% antifreeze mixed with 60 gallons of 15% antifreeze will provide 390 gallons of 70% antifreeze. Let the multiplier of 60 gallons be x, then considering the percentages of antifreeze in the solutions: (15 + 80x) ÷ (1 + x) = 70 ⇒ 15 + 80x = 70 + 70x ⇒ 10x = 55 ⇒ x = 5.5 Therefore mix 60 x 5.5 = 330 gallons of 80% antifreeze.
There may be a hole in the radiator?
70gallons