In the compound 4Fe₃O₂, there are 2 oxygen atoms per formula unit of Fe₃O₂. Since there are 4 formula units (as indicated by the coefficient 4), you multiply 2 oxygen atoms by 4, resulting in a total of 8 oxygen atoms. Therefore, there are 8 oxygen atoms in 4Fe₃O₂.
There are 6 oxygen atoms present on the reactant side of the chemical equation (4Fe + 3O_2 \rightarrow 2Fe_2O_3).
4Fe + 3O2 --> 2Fe2O3
4Fe + 3O2 2Fe2O3
Oxygen air. 2Fe + O2 -> 2FeO or 4Fe + 3O2 -> Fe2O3
The chemical reaction for rusting steel is: 4Fe (s) + 3O2 (g) -> 2Fe2O3 (s). This equation shows that iron reacts with oxygen in the presence of water to form iron oxide (rust).
This chemical reaction is: 4Fe(s) + 3O2(g) --> 2Fe2O3(s)
4Fe(s) + 3O2(g) ===> 2Fe2O3(s)
The balance equation would be 4Fe + 3O2 ==> 2Fe2O3, so the coefficients are 4, 3, 2.
The chemical symbol for iron is Fe and for oxygen is O.
Yes, the reaction 4Fe + 3O2 -> 2Fe2O3 is a combination reaction. In this reaction, iron (Fe) reacts with oxygen (O2) to form iron(III) oxide (Fe2O3).
4 Iron atoms + 3* Oxygen molecules + 6 Water molecules *Oxygen is diatonic, i.e. it only hangs around in pairs.
The chemical equation for the reaction of iron with oxygen to form rust is 4Fe + 3O2 -> 2Fe2O3.