In the compound 4Fe₃O₂, there are 2 oxygen atoms per formula unit of Fe₃O₂. Since there are 4 formula units (as indicated by the coefficient 4), you multiply 2 oxygen atoms by 4, resulting in a total of 8 oxygen atoms. Therefore, there are 8 oxygen atoms in 4Fe₃O₂.
There are 6 oxygen atoms present on the reactant side of the chemical equation (4Fe + 3O_2 \rightarrow 2Fe_2O_3).
4Fe + 3O2 --> 2Fe2O3
4Fe + 3O2 2Fe2O3
Oxygen air. 2Fe + O2 -> 2FeO or 4Fe + 3O2 -> Fe2O3
The chemical reaction for rusting steel is: 4Fe (s) + 3O2 (g) -> 2Fe2O3 (s). This equation shows that iron reacts with oxygen in the presence of water to form iron oxide (rust).
This chemical reaction is: 4Fe(s) + 3O2(g) --> 2Fe2O3(s)
4Fe(s) + 3O2(g) ===> 2Fe2O3(s)
The balance equation would be 4Fe + 3O2 ==> 2Fe2O3, so the coefficients are 4, 3, 2.
The chemical symbol for iron is Fe and for oxygen is O.
Yes, the reaction 4Fe + 3O2 -> 2Fe2O3 is a combination reaction. In this reaction, iron (Fe) reacts with oxygen (O2) to form iron(III) oxide (Fe2O3).
The chemical equation for the reaction of iron with oxygen to form rust is 4Fe + 3O2 -> 2Fe2O3.
The balanced chemical equation for the formation of Fe2O3 from Fe and O is: 4Fe + 3O2 -> 2Fe2O3