A 15 amp circut will be fine.
amps equals watts divided by volts.
The maximum amperage capacity required for a 30 amp range to operate efficiently is 30 amps.
My initial reaction was "absolutely not". The lighting circuit will only have a maximum feed capacity of 3 to 5 amps. For a garage opener this will be more than that. If you did manage to convert it, then you would almost certainly blow the circuit breaker and at the worst you may cause the wiring to set on fire due to overload. Basically, it's all about the maximum current that the opener draws when operating. I'm sure that it would exceed the capacity of the circuit. Additional question...I saw something at Home Depot that screws into a light socket and provides an electrical outlet. Would this work? I did a little research and found garage door openers ranging from 1.6 to 6 amps. Seems a little tight, but could it work?
A 15 amp should be fine, provided that #14 wire is used for the outlet. If #12 is used, then use a 20 amp breaker. Depending on what the motor voltage is makes a difference on what the wire size is. A 3/4 HP motor draws 13.8 amps at 115 volts and 6.9 amps at 230 volts. The motor feeder conductor must have an ampacity at least equal to 125% of the full load current rating of the motor. 13.8 x 125% = 17.25 amps. The conductor required on a motor using 120 volts is #12 rated at 20 amps. The breaker for this motor needs to be rated at 30 amps.
A stove typically requires around 40 to 50 amps to operate efficiently.
An electric stove or oven typically uses 20 amps to operate.
A pool pump motor which is drawing half the amps listed on its nameplate can indicate a problem with the windings or a lack of incoming current. Pumps will only draw as many amps as are required to operate under the current load.
A typical garage door motor uses about 3-5 amps while operating. This may vary depending on the specific model and size of the motor. It's important to check the motor's specifications for precise information.
Excessive resistance (drag), will cause motor to draw more amps (current flow) to operate.
The power required by the flashlight can be calculated using the formula P = V x I, where P is power in watts, V is voltage in volts, and I is current in amps. Plugging in the values, we get P = 12V x 0.25A = 3 watts. Therefore, the flashlight would require 3 watts of power to operate.
Garage door openers do not get "wired." They are sold with a standard 3-prong, 120VAC plug that is about two-feet long and plugs into a 15A, 120VAC outlet -- next to the location where the opener is installed. In the absence of a nearby AC outlet, you will need an extension to power you garage door opener. Well power doesn't get wired the wall mount and sensors do get wired use the directions they will tell you where hook the wires on the back of the opener.
An LED typically consumes around 20mA (0.02 amps) of current to operate. Exceeding this current limit can damage the LED.