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427 miles taking this route:

  1. Take I-75 NORTH from Naples all the way up to I-10 to JACKSONVILLE and TALLAHASSEE at EXIT 435 near Lake City. Follow signs on the exit ramp to I-10 EAST to JACKSONVILLE.
  2. Take I-10 EAST to I-95 NORTH to SAVANNAH via I-295 NORTH to bypass JACKSONVILLE (EXIT 356 off I-10 to get onto I-295, follow signs to I-295 NORTH to SAVANNAH ; EXIT 35B off I-295 to get onto I-95 NORTH to SAVANNAH).
  3. Take I-95 NORTH to SR-200/A1A to CALLAHAN and FERNANDINA BEACH at EXIT 373 (12 miles north of I-295).
  4. Turn right off the exit ramp and take SR-200/A1A NORTH to Amelia Island.
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14y ago

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