30 to 50 amps, it should be dedicated for the A/C.
To answer this question the voltage and amperage of the unit must be stated. Once this is given the generator size can be calculated.
The amount of amperage needed for a 220V well will depend on the wattage of the well pump. To calculate the amperage, divide the wattage of the pump by the voltage (220V) to get the amperage required.
You need a licensed mechanic/service technician to replace or otherwise service air conditioning systems that use freon.
You should never use a higher fuse rating than the wire size permits. If there were some fault in your central air that caused more current to flow than the rating of the wire, you could cause a fire.
To answer this question the motor voltage is needed.
There could be various reasons why your central air conditioning is running but there is no airflow, such as a clogged air filter, blocked vents, a malfunctioning blower motor, or a faulty thermostat. It is recommended to check these components and seek professional help if needed to diagnose and fix the issue.
To answer this question the resistance of the load is needed. I = E/R.
The 225 amps is the secondary output amperage. Look on the machines nameplate to find the input amperage. It is that amperage that is needed to size the feed wire and there the breaker size. When you find that amperage you may want to re question the breaker size.
The basic air conditioning units are either wall, window, portable or central units. Window units are placed in the window, wall units are installed in the wall, portable ones are usually powered with electricity and can be moved wherever needed. Central air conditioning units can cool an entire house instead of just one small area.
Yes, a central air conditioning system contains heat transfer coils. These coils are responsible for transferring heat between the refrigerant and the air, allowing the system to cool or heat the indoor space as needed.
4 tons. Rule of thumb is 1 ton for every 500 sq. ft.
Wire is sized by the amperage that it will carry. 5 kW is 5000 watts. The equation to find watts is W = Amps x Volts. The equation to find amps is Amps = Watts/Volts. As you can see a voltage is needed to calculate the amperage. Once the amperage is stated, the wire size can be given for that particular amperage.