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for preparing cement mortar C.M.(1:6) number of cement bags required are nearly 5.14 bags.

calculation: for preparing 1 cu.m wet C.M(1:6), dry material required is 25% extra.

therefore dry material required is 1.25 cu.m

hence cement required=1.25/(1+6)=0.178 cu.m

(sand required=0.178*6=1.068 cu.m)

density of cement=1440 kg/cu.m

=>cement required in kg=0.178*1440=256.32cu.m

wt. of cement in kg per bag=50kg

therefore no. of bags required is=26.32/50=5.14bags.

thank u.

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14y ago

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