mabey 2,000,000
To determine how many bags of concrete you need to fill a five-gallon bucket, first calculate the volume of the bucket. A five-gallon bucket holds about 0.67 cubic feet. If you're using a standard 60-pound bag of concrete, which typically yields about 0.45 cubic feet, you would need approximately 1.5 bags to fill the bucket. Always check the specific yield of the concrete mix you are using for the most accurate calculation.
To get a specific answer, we'd have to know the size of the tank. Since you used "an", let's assume an 18 gallon tank. 18 x 2.999 = 53.982. Rounded to the nearest cent (hundredth), that's $53.98
To determine how many 12-ounce cans can be filled with 8 milliliters, we first convert 12 ounces to milliliters. There are approximately 29.57 milliliters in one ounce, so 12 ounces is about 355 milliliters. Dividing 8 milliliters by 355 milliliters shows that 8 milliliters is far less than one can, meaning it will not fill even one 12-ounce can.
To determine how many Morgan silver dollars can fill a five-gallon bucket, we first need to calculate the volume of a single Morgan silver dollar. The diameter of a Morgan silver dollar is approximately 38.1 mm, with a thickness of around 2.4 mm. Using these measurements, we can calculate the volume of a single coin. Once we have the volume of a single coin, we can then calculate how many of these coins would fit into a five-gallon bucket, which has a volume of 18,927 cubic centimeters.
You can achieve this by first filling the 3-gallon container with oil, then pouring it into the 5-gallon container. Next, fill the 3-gallon container again and pour it into the 5-gallon container until it's full (leaving 1 gallon in the 3-gallon container).
Notation: ( x , y ) where x is the amount of water in the 3-gallon container and y is the amount of water in the 5-gallon container1. Fill the three-gallon container ( 3 , 0 )2. Pour the three gallons into the 5-gallon container ( 0 , 3 )3. Fill the three-gallon container ( 3 , 3 )4. Fill the five-gallon container with the three-gallon container, leaving 1 gallon in the three gallon container ( 1 , 5 )5. Pour out the water from the five-gallon container ( 1 , 0 )6. Pour the water from the three-gallon container into the five-gallon container ( 0 , 1 )7. Fill the three-gallon container ( 3 , 1 )8. Pour the water from the three-gallon container into the five-gallon container ( 0 , 4 )Another great answer here:[See below for the related link]
16 halfpint cartons of water are needed to fill the gallon container
1. Fill the 2 gallon container with water. 2. Pour all the water in the 2 gallon container into the 3 gallon container. 3. Refill the 2 gallon container 4. Fill the 3 gallon container the rest of the way with the 2 gallon container. You will have 1 gallon left in the 2 gallon container without using the 5 gallon container. P.S Whose bomb are you trying to defuse?
fill 3 gallon container with juice and poor into 5 gallon container you now have 3 gallons in he container. now refil the 3 gallon container and fill the 5 gallon the rest of the way. now you have used up 2 gallons filling the 5 gallon container and you have 1 gallon left in the 3 gallon container.
1. Completely fill the 4 gallon container. 2. Pour 3 of the 4 gallons into the 3 gallon container, leaving 1 gallon in the 4 gallon container. 3. Empty the 3 gallon container and pour the 1 remaining gallon from the 4 gallon container into the 3 gallon container. 4. Fill the 4 gallon container. Now you have a total of 5 gallons, 4 in the 4 gallon container and 1 in the 3 gallon.
One quart
To fill the 30-gallon tank, you would need to use the pesticide and water in a ratio of 4 ounces to 1 gallon. Therefore, you would need 120 ounces (30 gallons x 4 ounces) of pesticide to fill the 30-gallon tank.
It is impossible to measure out exactly 1 gallon into a 4 gallon container, unless the container has appropriate markings for measurement. However, if you had a 2nd container available, it may be possible to derive a 1 gallon measurement. Assuming a 2nd container of size: 1 Gallon: Just use the 2nd container 2 Gallon: Impossible 3 Gallon: Fill the 4 gallon container completely, then pour it into the 3 gallon container until full. You should have exactly 1 gallon left in the 4 gallon container. 4 Gallon: Impossible 5 Gallon: Fill the 5 gallon container until it is full, then dump it's contents into the 4 gallon container, leaving exactly 1 gallon left in the 5 gallon container. 6 Gallon: Impossible 7 Gallon: Fill the 4 gallon container completely, then empty it's contents into the 7 gallon container. Repeat this process, and when the 7 gallon container is full, there should be exactly 1 gallon left in the 4 gallon container. 8 Gallon: Impossible 9 Gallon: Fill the 9 gallon container completely, then use it to fill the 4 gallon container. Once the 4 gallon container is full, empty it and repeat. After pouring from the 9 gallon container twice, you will end up with exactly 1 gallon left. 10 Gallon: Impossible This pattern repeats for all containers that satisfy the following equations: C*n+1 C*n-1 Where C is the size of the original container (4 in this case), and n is all whole numbers greater than 0. The only additional case would be a 2nd container size of 1.
Depends if we are talking US gallons (used in USA) or imperial gallons (used everywhere else). US Gallons 1 = 128 fl ounces. , so (128 * 5) / 32 = 20 Imp. Gallons 1 = 160 fl Ounces, so (160 * 5) / 32 = 25
you fill the 3 gallon up then put it in the 5 gallon then fill the 3 gallon up again and poor as much as u can in the 5 gallon then u will be left with 1 gallon in the 3 gallon bucket
Well, honey, it's simple math. Fill up the 9 gallon container, pour it into the 4 gallon container until it's full, leaving you with 5 gallons in the 9 gallon container. Then empty out the 4 gallon container, pour the remaining 5 gallons from the 9 gallon container into the 4 gallon container, and finally fill up the 9 gallon container again. Voila, you've got yourself 6 gallons of water!