Assuming "2 7" is 27, N is -19.
It is any one of infinitely many fractions of the form n/n where n is a no-zero integer.
As we know that the formula of n!=n(n-1)! so 8!=8*(8-1)! =8*7! =8*7*6! =8*7*6*5! =8*7*6*5*4! =8*7*6*5*4*3! =8*7*6*5*4*3*2! =8*7*6*5*4*3*2*1! =8*7*6*5*4*3*2*1 =40320 so the factorial of the given no. 8 is 40320.
For n = 4, 4! = 4*3*2*1 = 24 and 24 = 2*2*2*2 = 16 So the statement is true for n = 4. Suppose it is true for n = k, that is, k! > 2k Then (k+1)! = (k+1)*k! > (k+1)*2k (since k! > 2k) > 2*2k (since k >= 4 > 2) = 2k+1 So if the statement is true for n = k then it must be true for n = k+1. Therefore, since it is true for n = 4 it must be true for all n > 4.
The GCF of 30 n^4 and 45 n^2 is 15 n^2. The GCF of 30 and 45 is 15, and n squared is a factor of n^4.
It is already in its simplest form so it can only change if you multiply it:- 4/7 = (4.n)/(7.n) So fractions which are equivalent to 4/7 = 8/14, 12/21, 16/28, 20/35, 24/42, 28/49,...
7 - 3n: n = 0: 7-3(0) = 7 n = 1: 7-3(1) = 4 n = 2: 7-3(2) = 1 n = 3: 7-3(3) = - 2 n = 4: 7-3(4) = - 5 n = 5: 7-3(5) = - 8
n(n-1)/2+1Example for n-7:1, 2, 4, 7, 11, 16, ?7(7-1)/2+17(6)/2+142/2+126+127
3n+3=n+7 3n+3-n=n+7-n (subtract n from both sides) 2n+3=7 2n+3-3=7-3 (subtract 3 from both sides ) 2n=4 2n/2=4/2 (divided by 2 on both the sides) n=2 Answer: n=2
It is the central number in the ordered set. To find the median of a list of numbers, you have to put the numbers from least to greatest and then count in an equal number from each side. For n data values, the median will be the ordinal number (n+1)/2 For even numbers of values, it is the average of the 2 middle numbers. Example : 1 2 4 4 5 6 7 7 7 the median is 5 1 2 4 4 4 5 6 7 7 7 the median is 4.5 (4 + 5) / 2
Any number can be the average. For example, 7 is the average of 7-n and 7+n for any number n.
-9 + n/4 = -7 Add 9 to both sides: n/4 = +2 Multiply both sides by 4: n = 8
To find the value of (n-2)^2 + n-1 when n=4, we simply substitute 4 for n in the expression: (n-2)^2 + n-1 When we do this, the expression becomes: (4-2)^2 + 4-1 Now we need to simplify the expression within the parentheses first. The expression within the parentheses is (4-2)^2, which means we need to subtract 2 from 4 and then square the result. So, we get: 2^2 Which equals 4. Now we can substitute this value back into the original expression to get: 4 + 4-1 Next, we simplify the expression 4-1, which equals 3. So, the expression becomes: 4 + 3 And we can simplify that further to get: 7 So, when n=4, the value of (n-2)^2 + n-1 is 7
N = -36
Call the unknown number n. Then, from the problem statement, {4[(n + 7 - 2) - n]} - 2 = 18. This is always true because [(n + 7 - 2) - n] is simply 5.
n=3
It is any one of infinitely many fractions of the form n/n where n is a no-zero integer.
IF you meant n/7=4 then n=28