m and n are 70 and 90
It shows the relationship of factors to multiples. A factor times a factor equals a multiple of both of those factors.
To find the multiples of 9 up to 9000, you can use the formula: (9 \times n), where (n) is a positive integer. The first few multiples of 9 are 9, 18, 27, 36, and so on. To find the multiples of 9 up to 9000, divide 9000 by 9, which equals 1000. Therefore, the multiples of 9 up to 9000 are all the multiples of 9 from 9 to 9000, inclusive.
Here are the first 10 multiples of 8, that is 8 times 1 through to 8 times 10. 8,16,24,23,40,48,56,64,72,10
6 times 13 equals 78 3 times 26 equals 78 2 times 39 equals 78 and 1 times 78 equals 78
47184
times equals sets of
60x2
There is an infinite number of multiples of 4. Multiples of 4 can be 0, 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, etc. 4 can be multiplied to get those numbers, and that makes them multiples of 4. 4 times 0 equals 0, 4 times 1 equals one, 4 times 2 equals 8, 4 times 3 equals 12, and so on.
752 times 7 =5264 994 times 7 =6958 456 times 7 =3192
The answer is 135. 15 times 9 equals 135 27 times 5 equals 135
There are 50 multiples of 80 between 1 and 4000, as 4000 divided by 80 equals 50. However, the question asks for the number of occurrences of the digit "8" in the range from 1 to 4000, not the number of multiples of 80. The digit "8" appears in the units place for numbers 8, 18, 28, ..., 3998, occurring 500 times. Additionally, it appears in the tens place for numbers 80, 81, ..., 89, 180, 181, ..., 189, and so on, occurring 400 times. Therefore, the digit "8" appears 900 times in the range from 1 to 4000.
2178
4.83333333 (the digit 3 repeats indefinitely).
A multiple of 50 is any number in the 50 times table. So the 3 digit multiples of 50 are: 100, 150, 200 ... 850, 900, 950.
There is no integral solution for that. The factor pairs of 114 are (114,1)(57,2)(38,3)(19,6)
The product of 12 times 15 is 180. This can be calculated by multiplying 12 by 15, as each digit in the first number is multiplied by each digit in the second number, and then adding the results together. In this case, 12 times 15 equals 180.
A digit in the thousands place is 10 times greater than the same digit in the hundreds place. For example, if the digit is 3, the value in the thousands place is 3,000, while in the hundreds place it is 300. Therefore, 3,000 divided by 300 equals 10, confirming that the thousands place digit is 10 times greater.