No.
Tan is what white people like me get when they're out in the sun a lot.
I get lobster red & wish I could be tan. Tan is a color-lightish brown/beige.
hispanic is not a race their are white, black, tan,and Asian hispanic
it depends on your race. if your are black than your skin is brown. if you are white than your skin is peach or if you got a tan, tan. i am not raciest.
yes mate black as
The Amazing Race - 2001 Your Tan Is Totally Cool 22-5 was released on: USA: 17 March 2013 Australia: 24 March 2013
I am Mexican , but I am much whiter toned then others, I get tan, but if I'm out in the sun to long I get a gross dark coulour
To be like the other race.
If you mean physically then it would be he had curly hair, and tan skin. Most characteristics of a Jew by race.
tan(9) + tan(81) - tan(27) - tan(63) = 4
Judging by her real last name (Tan) I'm going to go with Chinese. On her model profile it says her ethnicity is Asian.
Tan, or as most ppl like to say, white. Her dad is African Anerican, black.
Tan Tan
tan (A-B) + tan (B-C) + tan (C-A)=0 tan (A-B) + tan (B-C) - tan (A-C)=0 tan (A-B) + tan (B-C) = tan (A-C) (A-B) + (B-C) = A-C So we can solve tan (A-B) + tan (B-C) = tan (A-C) by first solving tan x + tan y = tan (x+y) and then substituting x = A-B and y = B-C. tan (x+y) = (tan x + tan y)/(1 - tan x tan y) So tan x + tan y = (tan x + tan y)/(1 - tan x tan y) (tan x + tan y)tan x tan y = 0 So, tan x = 0 or tan y = 0 or tan x = - tan y tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = - tan(B-C) tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = tan(C-B) A, B and C are all angles of a triangle, so are all in the range (0, pi). So A-B and B-C are in the range (- pi, pi). At this point I sketched a graph of y = tan x (- pi < x < pi) By inspection I can see that: A-B = 0 or B-C = 0 or A-B = C-B or A-B = C-B +/- pi A = B or B = C or A = C or A = C +/- pi But A and C are both in the range (0, pi) so A = C +/- pi has no solution So A = B or B = C or A = C A triangle ABC has the property that tan (A-B) + tan (B-C) + tan (C-A)=0 if and only if it is isosceles (or equilateral).