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What else can I help you with?
Is a meter longer tan a centimeter?
Yes. There are 100 centimeters in a meter. centi means 1 hundred. For example century is 100 years.
How much fall in a 8 degree roof over 1 meter?
To calculate the fall (or drop) of an 8-degree roof over a distance of 1 meter, you can use the tangent function from trigonometry. The formula is: fall = distance × tan(angle). For an 8-degree angle, the fall is approximately 1 meter × tan(8°), which equals about 0.14 meters, or 14 centimeters.
How much is a 3 degree fall over 1 meter?
To calculate the vertical drop over a given horizontal distance due to a slope, we use the formula: vertical drop = horizontal distance * tan(slope angle). Given a 3-degree slope over 1 meter, the vertical drop would be 1 meter * tan(3 degrees), which is approximately 0.0524 meters or 5.24 centimeters. This means that for every 1 meter of horizontal distance, the elevation would decrease by about 5.24 centimeters.
A tree casts a shadow of 23 meters when the angle of elevation of the sun is 23 Find the height of tree to the nearest meter?
Use the tangent ratio: 23*tan(23) = 9.762920773 Answer: 10 meters to the nearest meter
How much fall in a 11 degree roof over 1 meter?
To calculate the fall (or rise) for an 11-degree roof over 1 meter, you can use the tangent of the angle. The fall can be calculated as: fall = 1 meter * tan(11 degrees). This gives approximately 0.193 meters, or 19.3 centimeters of fall over 1 meter of horizontal distance.
Tan 9 plus tan 81 -tan 27-tan 63?
tan(9) + tan(81) - tan(27) - tan(63) = 4
What is a antonym of pale?
Tan Tan
The pitch of your roof is 3 degrees how much does it rise over a meter?
To calculate the rise of a roof with a 3-degree pitch over a meter, you can use the tangent function in trigonometry. The rise is equal to the tangent of the angle multiplied by the run (distance), which in this case is 1 meter. Therefore, the rise is approximately ( \tan(3^\circ) \times 1 \text{ meter} ), which is about 0.0524 meters, or approximately 5.24 centimeters.
If for a triangle abc tan a-b plus tan b-c plus tan c-a equals 0 then what can you say about the triangle?
tan (A-B) + tan (B-C) + tan (C-A)=0 tan (A-B) + tan (B-C) - tan (A-C)=0 tan (A-B) + tan (B-C) = tan (A-C) (A-B) + (B-C) = A-C So we can solve tan (A-B) + tan (B-C) = tan (A-C) by first solving tan x + tan y = tan (x+y) and then substituting x = A-B and y = B-C. tan (x+y) = (tan x + tan y)/(1 - tan x tan y) So tan x + tan y = (tan x + tan y)/(1 - tan x tan y) (tan x + tan y)tan x tan y = 0 So, tan x = 0 or tan y = 0 or tan x = - tan y tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = - tan(B-C) tan(A-B) = 0 or tan(B-C) = 0 or tan(A-B) = tan(C-B) A, B and C are all angles of a triangle, so are all in the range (0, pi). So A-B and B-C are in the range (- pi, pi). At this point I sketched a graph of y = tan x (- pi < x < pi) By inspection I can see that: A-B = 0 or B-C = 0 or A-B = C-B or A-B = C-B +/- pi A = B or B = C or A = C or A = C +/- pi But A and C are both in the range (0, pi) so A = C +/- pi has no solution So A = B or B = C or A = C A triangle ABC has the property that tan (A-B) + tan (B-C) + tan (C-A)=0 if and only if it is isosceles (or equilateral).
How much does 1.5 degrees fall over 1 meter?
To calculate the vertical drop over a horizontal distance of 1 meter for an angle of 1.5 degrees, you can use the tangent function. The drop can be found using the formula: drop = distance × tan(angle). For 1 meter at 1.5 degrees, the drop is approximately 0.026 meters, or 2.6 centimeters.
What is the height of a building when the distance between its angles of elevation which are 29 degrees and 37 degrees is 30 meters on level ground?
Using trigonometry its height works out as 63 meters to the nearest meter. -------------------------------------------------------------------------------------------------------- let: h = height building α, β be the angles of elevation (29° and 37° in some order) d be the distance between the elevations (30 m). x = distance from building where the elevation of angle α is measured. Then: angle α is an exterior angle to the triangle which contains the position from which angle α is measured, the position from which angle β is measured and the point of the top of the building. Thus angle α = angle β + angle at top of building of this triangle → angle α > angle β as the angle at the top of the building is > 0 → α = 37°, β = 29° Using the tangent trigonometric ratio we can form two equations, one with angle α, one with angle β: tan α = h/x → x = h/tan α tan β = h/(x + d) → x = h/tan β - d → h/tan α = h/tan β - d → h/tan β - 1/tan α = d → h(1/tan β - 1/tan α) = d → h(tan α - tan β)/(tan α tan β) = d → h = (d tan α tan β)/(tan α - tan β) We can now substitute the values of α, β and x in and find the height: h = (30 m × tan 37° × tan 29°)/(tan 37° - tan 29°) ≈ 63 m
How much fall in a 3 degree roof over 2 meter?
To calculate the fall (or slope) of a 3-degree roof over a distance of 2 meters, you can use the formula: fall = distance × tan(angle). In this case, the fall would be approximately 2 meters × tan(3 degrees), which equals about 0.105 meters, or 10.5 centimeters. Thus, the roof would fall approximately 10.5 cm over the 2-meter span.
