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10.0 moles of a liquid are converted to its vapor at its boiling point 100 K and at 1 ATM The molar heat of vaporization of the liquid is 200 kjmole at this T and P Calculate work and heat?
Updated: 10/31/2022
Wiki User
∙ 15y agoBest Answer
10 mol x 200 kJ/mol = 2000 kJ
S = 20 kJ/K
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∙ 15y agoThis answer is:
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Earn +20 ptsQ: 10.0 moles of a liquid are converted to its vapor at its boiling point 100 K and at 1 ATM The molar heat of vaporization of the liquid is 200 kjmole at this T and P Calculate work and heat?
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