If you assume hardy-weinburg equilibrium, then:
let B = frequency of black allele (dominant)
b = frequency of white allele (recessive)
BB (or B^2) = frequency of homozygous black sheep
2Bb = frequency of heterozygous black sheep
bb (or b^2) = frequency of white sheep
Since 9% of the sheep are white, the frequency of white sheep is 0.09, or bb = 0.09, so b=.3, which means B = 1-b = 1-.3 = 0.7
You should check to make sure that the hardy-weinburg assumption holds:
BB = 0.49
2Bb = 0.42
And BB + 2Bb = 0.91, which is the frequency of black sheep. ?The hardy-weinburg assumption is valid!
The name of the gene pair that consists of a dominant and recessive allele, i.e. (Xx) will be a heterozygous allele. In this situation, the characteristics of the dominant characteristic will mask that of the recessive allele. People have have a heterozygous genotype may be carriers for diseases that reside on the recessive allele.
A gene pair that consists of a dominant allele and a recessive allele is called a heterozygous gene. A homozygous gene, meanwhile, is a gene pair consisting of two dominant alleles or two recessive alleles.
formula: p2 + 2pq + q2 = 1 p+q=1 p = dominant (A) allele frequency q = recessive (a) allele frequency q2 = homozygous recessive frequency p2 = homozygous dominant frequency 2pq = heterozygous frequency
Homozygous recessive genotype
There is dominant and there is recessive. There is no dominant recessive. A dominant gene will always be expressed when present, such as in the homozygous dominant genotype (RR), or heterozygous genotype (Rr). A recessive allele is only expressed when the genotype is homozygous recessive (rr).
A gene pair that consists of 2 dominant or 2 recessive alleles is considered homozygous dominant or homozygous recessive.
The name of the gene pair that consists of a dominant and recessive allele, i.e. (Xx) will be a heterozygous allele. In this situation, the characteristics of the dominant characteristic will mask that of the recessive allele. People have have a heterozygous genotype may be carriers for diseases that reside on the recessive allele.
Some observable traits in humans are dimples, earlobes, tongue-rolling, cleft chin, hairline, and freckles. The relationship between the frequency of a trait in a population and whether the trait is dominant or recessive because in inherited human traits, the offspring can either have dimples or no dimples.
Actually a chromosome consists of many genes/alleles and is neither recessive or dominant in and of itself.
A gene pair that consists of a dominant allele and a recessive allele is called a heterozygous gene. A homozygous gene, meanwhile, is a gene pair consisting of two dominant alleles or two recessive alleles.
formula: p2 + 2pq + q2 = 1 p+q=1 p = dominant (A) allele frequency q = recessive (a) allele frequency q2 = homozygous recessive frequency p2 = homozygous dominant frequency 2pq = heterozygous frequency
Because it has things
Homozygous Dominant or Homozygous Recessive, accordingly.
Heterozygous dominant pair.
It depends on the family but I assume that its a recessive gene.
The name of the gene pair that consists of a dominant and recessive allele, i.e. (Xx) will be a heterozygous allele. In this situation, the characteristics of the dominant characteristic will mask that of the recessive allele. People have have a heterozygous genotype may be carriers for diseases that reside on the recessive allele.
This is a principle of population genetics based on the Hardy-Weinberg Principle. A trait that is neither selected for nor against will remain in the population at the same frequency. In most populations the frequency values can be back calculated from the percentage of the population that is homozygous recessive. The basic equations are p+q=1 and p (squared) + 2pq + q (squared)=1 The value of q (squared) is the frequency of homozygous recessive individuals in the population. So if 20% of the population is homozygous recessive, then q (squared) is .20. This makes q=.45 (approx.) So, in order to produce a population where 20% of all individuals are homozygous recessive a full 45% of all the alleles at that gene locus are recessive. p=.55 p+q=.55+.45=1.0 Now all the numbers for the homozygous dominant and heterozygotes can be calculated. The approximate percent of the population that is homozygous dominant is 30% with 50% of the population represented by heterozygotes. .3+.5+.2=1 As the gene frequency for an allele decreases the less likely two individuals that are heterozygous for the trait will be to breed and produce either a homozygous recessive individual or a homozygous dominant. In the case where a characteristic is dominant and has a low frequency, the trait will be seen in family lines but rarely has the opportunity to be passed beyond a small population because there is no selection for the characteristic. An example of this is 6 fingered (polydactyl) individuals, which is a dominant trait. They exist in the population but they are rarely seen.