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A recessive allele t is responsible for a condition called distonia a man who has this condition marries a woman who doesnt one of their four children has the conditon what are the pssible genotypes?
Wiki User
∙ 13y ago
Firstly, if the condition is recessive, both the man and the child with the condition must have the genotype tt.
The mother must have the genotype Tt. This is because if she had TT, all of the children would be Tt and not have the condition. If she were tt, she would have the condition as well.
Therefore if the father has tt and the mother has Tt, the other 3 children who do not have the condition must all have the genotype Tt.
So:
Mother - Tt
Father - tt
Affected child - tt
Other children - Tt
Wiki User
∙ 12y ago
Wiki User
∙ 13y agoIf this was a autosomal recessive condition then the fathe would be autosomal recessive the mother would be heterozygous for the condition and the three kids who did not have the condition would be heterozygous. The kid who had the condition would be recessive for the condition.
Wiki User
∙ 14y agoThe father is tt: and the mother is Tt
*Casey*
Wiki User
∙ 14y agoIf the man is homozygous recessive, and the woman is homozygous dominate then the possible genotypes are Tt. If the man is heterozygous, then the possible genotypes are TT, Tt, and tt.
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What can you predict about the offspring if you know the genotypes of the parents?
So, if one parent is Aa (heterozygous) and the other parent is aa (homozygous recessive) the punnett square would look like this: ___|_A__|__a_ _a_|_Aa_|_aa_ _a_|_Aa_|_aa_ The genotypes of the offspring 50% heterozygous and 50% homozygous recessive
Is the punnet square used to find the probability of genotypes and phenotypes?
A Punnet square is used to find the probablitiy of certain genetic traits in the offspring of an organism (example: the traits in the children) by taking the trait of each possible parent gamete (sex cell) and combining the combinations within the squares.Example:A aA AA Aaa Aa aaSo the offspring here have a 25% chance of being homozygous (both dominant) dominant for the trait, 50% heterozygous (one dominant and one recessive) dominant for the trait, and 25% (homozygous (both recessive)) recessive for the trait.
Brown eyes are dominant over blue eyes in humans The genetic makeup of blue-eyed children who have brown-eyed parents must be?
B (dominant) is for brown and b (recessive) is for blue. If both parents have brown eyes, for them to have a blue-eyed child their genotypes (the combination of b's) must both be Bb, because they both need to provide a little b (to have blue eyes you must be double recessive (bb)). This is worked out using a Punnett Square. (example: https://mcglynn-bioreview4.wikispaces.com/file/view/basicpunnetsquare.jpg)
Many inherited disorders of humans appear in children of parents who do not have the disorder how can you explain that the parents do not have the disorder but the child does?
The disorder is controlled by a recessive factor.
If someone in a family is a purebred and he marries someone with a recessive trait will his children still be considered purebreds?
yes the children would be cause they have purebred blood in them.....
Which is expressed a dominant or recessive allele and which is passed on to the offspring?
The dominant allele will always show over the recessive, and both can be passed onto the offspring. To find out exactly which genotypes the children can have you need to make a punnet square!
What can you predict about the offspring if you know the genotypes of the parents?
So, if one parent is Aa (heterozygous) and the other parent is aa (homozygous recessive) the punnett square would look like this: ___|_A__|__a_ _a_|_Aa_|_aa_ _a_|_Aa_|_aa_ The genotypes of the offspring 50% heterozygous and 50% homozygous recessive
A man who has dystonia marries a woman who doesn't one of their children has the condition what are the possible genotypes of the man and woman?
Assuming the dystonia is hereditary and is a recessive gene which will be called "d" for simplicity, that means the man must be "dd" and the woman is "Dd". This is the only way they could have a child who is "dd" like the father, but not the mother.
A man with freckles and a women without freckles with 3 kids with freckles and 1 without what is the genotypes of the parents and children?
The man must have a dominant gene for freckling and a recessive gene for no freckling. The woman has both recessive genes for no freckling. Therefore, there should be a 50% chance of getting the freckling gene and freckle in this family. If they had more children, chances are 50/50 that the baby will freckle.
What is automasal trait?
With an autosomal recessive inheritance pattern, a person needs to have 2 copies of a gene change to have the condition. In most cases, people with an autosomal recessive condition get one gene change from the mother and one gene change from the father.The parents of a person with an autosomal recessive condition may not have the condition themselves, since each parent only needs to have one copy of the gene change. People with one copy of the gene change are called carriers, who do not have the condition, but are more likely to have children with the condition. Other family members (uncles, aunts, brothers, cousins, etc) may also be carriers.
Why genetics use Punnett squares?
Geneticists use punnet squares to determine dominant and recessive alleles in organisms such as humans. For example, a monohybrid cross can be used to show hair color. Alleles from parents are used to determine the probability of certain traits to be more or less prevalent.
If the parents are AO and BO genotypes for the ABO blood group their children could include what genotypes?
25% AB, 25% A, 25% B and 25% O
Is the punnet square used to find the probability of genotypes and phenotypes?
A Punnet square is used to find the probablitiy of certain genetic traits in the offspring of an organism (example: the traits in the children) by taking the trait of each possible parent gamete (sex cell) and combining the combinations within the squares.Example:A aA AA Aaa Aa aaSo the offspring here have a 25% chance of being homozygous (both dominant) dominant for the trait, 50% heterozygous (one dominant and one recessive) dominant for the trait, and 25% (homozygous (both recessive)) recessive for the trait.
AAA AAA what are the possible genotypes and phenotypes os their children?
Possible genotypes would be AA and Aa. Phenotypes cannot be determined here because they are the physical, observable results of a genotype.
Why is a man genotype Cc?
CC is the phenotype for sickle cell anemia. They can also have SS or SC genotypes. These people can marry only some other genotypes and not have their children develop the disease.
If a women with type O blood and a man with type AB blood have childrenwhat are the childrenwhat are the children's possible genotypes?
Parentsblood types: A and Bgenotypes: IAi and IBiChildrenblood types: A, B, O, and ABgenotypes: IAi, IBi, Ii, and IAIB(capital A's and B's are superscript)
Can a blue eyed parent and a brown eyed parent have blue eyed children?
The blue eyed parents may have heterozygous genotypes with the dominant gene and recessive gene for blue and brown eyes respectively. During segregation of gametes, their is a likelihood that their child may inherit the recessive genes from both parents. Consequently, their child will have brown eyes.
