NOW. Colourblindness we will assume, is a Sex-Linked Disorder. Hence, the sex chromosomes are involved in determinig the phenotypes of the children. XY --male XX--female XbY--colourblind male XBXb --normal female Cross: (parents) Xby * XBXb F1 progeny/offspring XBXb, XbXb, XBY, XbY 50 % of the children will be colourblind. This is a very simple question. You also need to clarify within the question if it is sex linked or autosomal.
The probability of a colorblind child being born is 50%. This is because the male passes his Y chromosome to all his sons, and since he is colorblind, his sons will inherit the colorblind gene from him. The daughters will inherit their X chromosome from the mother and have a 50% chance of being carriers like her.
it depends on the husbands genotype, if it is a recessive gene (bb) then there is a 50 50 chance of either straight or curly hair. if the husbands straight hair is a heterozygous gene, then there is a 70% chance for either straight or curly hair.
Firstly, if the condition is recessive, both the man and the child with the condition must have the genotype tt. The mother must have the genotype Tt. This is because if she had TT, all of the children would be Tt and not have the condition. If she were tt, she would have the condition as well. Therefore if the father has tt and the mother has Tt, the other 3 children who do not have the condition must all have the genotype Tt. So: Mother - Tt Father - tt Affected child - tt Other children - Tt
There is a 25% chance that their first child will have type O blood if both parents are heterozygous for blood type A and B. This is because the child could inherit an O gene from each parent, resulting in blood type O.
No, the children would not be considered purebred. Their genetic makeup would be a mix of the purebred parent's dominant traits and the recessive traits from the other parent, making them a hybrid of the two.
50%
there is a 50% chance that the child will be colorblind. If it is a boy, it will be colorblind, but if it is a girl, it will only be a carrier. Mother's chromosome is XrXr and Father's Chromosome is XRY, which means the children's genotypes will be XRXr if girl and XrY if a boy.
50% of their children are expected to have a widow's peak. When a heterozygous male (Ww) with a widow's peak gene marries a female with a straight hairline (ww), their offspring have a 50% chance of inheriting the widow's peak gene from the father.
The probability of a colorblind child being born is 50%. This is because the male passes his Y chromosome to all his sons, and since he is colorblind, his sons will inherit the colorblind gene from him. The daughters will inherit their X chromosome from the mother and have a 50% chance of being carriers like her.
Assuming that the man who has normal vision is homozygous for normal vision, the couple's daughter will either be homozygous for normal vision or heterozygous (normal vision but carrier for color blindness) for normal vision. In light of this, the couple's daughter will not be color blind.
All of their children are expected to be heterozygous for the trait (Tt), which means they would be tall (dominant phenotype). The recessive trait for being short would only manifest if both copies of the gene were recessive.
Colorblindness is an X-linked recessive disorder. This means girls (who have the sex chromosomes XX) must have a colorblind X from dad and a colorblind X from mom. Boys only need to have one colorblind X to be colorblind because they have sex chromosomes XY (and have only 1 X). If the dad has it, he has the colorblind X. If the daughter has it, she must have gotten her mom's colorblind X. If the mom is colorblind, then every child they have will be colorblind. If the mom is not colorblind, then she must be a carrier - she must have 1 normal X and 1 colorblind X. Mom is either colorblind (with 2 colorblind Xs) or she is a carrier. Dad is definitely colorblind.
its called disgusting who marries there children unless you are in a different country but still eww
Yes, I think so. He marries Sakura Haruno and has kids.
According to Mendelian genetics, if the male is heterozygous for the widows peak trait (Ww) and the female has a straight hairline (ww), 50% of their children are expected to have a widows peak (Ww) and the remaining 50% of their children are expected to have a straight hairline (ww).
In the Epilogue, Harry marries Ginny and has three children. Hermione marries Ron and they have one child.
it depends on the husbands genotype, if it is a recessive gene (bb) then there is a 50 50 chance of either straight or curly hair. if the husbands straight hair is a heterozygous gene, then there is a 70% chance for either straight or curly hair.