recessive trait only appear when an individual is homozygous recessive, both alleles must code for the recessive trait
Homozygous for that trait.
rule of dominance
Homozygous
'Albinism' (being an albino, without skin pigmentation) is an example of a recessive trait. Specifically, it is an expressed recessive trait, because that person does not have the dominant gene at all, only two copies of a recessive gene. For a person to be an albino, his/her parents BOTH had to have the recessive gene and the offspring had to inherit THOSE TWO copies and can now only 'express' the recessive gene. There is no dominant gene to undo the albino trait. Side note: there is more than one form of albinism recognized in medical science, but all are examples of recessive traits. Another example of a recessive trait would be 'sickle-cell disease/anemia.'
reappears in some plants in the F2 generation
50%. There are four possible outcomes of the cross:dominant trait from "dad", dominant trait from "mom"recessive trait from "dad", dominant trait from "mom"dominant trait from "dad", recessive trait from "mom"recessive trait from "dad", recessive trait from "mom"Therefore, to get hybrid offspring (one dominant, one recessive), you have a 2 out of 4 chance.
he crossed two pure lines
All the offspring will be heterozygous with a phenotype showing the dominant trait. Let the alleles be H (dominant) and h (recessive). All the gametes from the first individual will be H, and from the other, h. Thus all the offspring must be Hh.
A family tree is a great idea, but the science is based on probability. The probability that a recessive trait will show up in a family is 25% if both parents are carriers. In order for a recessive trait to show up in a person, he/she must inherit a copy of the recessive trait from both parents. If one parent is recessive, let's say "rr" and the other parent is a carrier, say "Rr", the probability is 50%. If both parents are recessive, the probability is 100% (rr x rr). If neither parent carries the trait the probability is 0% (RR x RR). BUT, this only tells you what MIGHT happen. We all know that the probability of having a boy is 50:50, but we all know families of all boys. So it would be interesting to see if the probability works out in your family. If you do a search on the web for "genetics" or "probability and genetics" you will get plenty of hits. vanhoeck
'Albinism' (being an albino, without skin pigmentation) is an example of a recessive trait. Specifically, it is an expressed recessive trait, because that person does not have the dominant gene at all, only two copies of a recessive gene. For a person to be an albino, his/her parents BOTH had to have the recessive gene and the offspring had to inherit THOSE TWO copies and can now only 'express' the recessive gene. There is no dominant gene to undo the albino trait. Side note: there is more than one form of albinism recognized in medical science, but all are examples of recessive traits. Another example of a recessive trait would be 'sickle-cell disease/anemia.'
reappears in some plants in the F2 generation
A recessive trait can only be passed along if both parents carry at least one of the recessive genes to the child. If both parents manifest the trait (that is, if both parents have both recessive genes), then the child will manifest (that is, carry both recessive genes and display) the recessive trait. If one parent manifests and the other parent only carries the trait (that is, carries one dominant and one recessive gene) then the child will definitely carry and have a 50% chance of manifesting. If both parents carry the recessive, the child is 25% likely not to carry the trait at all, 50% likely to carry and 25% likely to manifest the trait.
50%. There are four possible outcomes of the cross:dominant trait from "dad", dominant trait from "mom"recessive trait from "dad", dominant trait from "mom"dominant trait from "dad", recessive trait from "mom"recessive trait from "dad", recessive trait from "mom"Therefore, to get hybrid offspring (one dominant, one recessive), you have a 2 out of 4 chance.
he crossed two pure lines
Punnet squares help determine what trait will show up in offspring of two living things. They show all the possible match-ups of dominant and recessive genes, and show you what percent chance it is that a child will have a certain trait. Punnet squares are used for one trait.
All the offspring will be heterozygous with a phenotype showing the dominant trait. Let the alleles be H (dominant) and h (recessive). All the gametes from the first individual will be H, and from the other, h. Thus all the offspring must be Hh.
The allele not expressed would be recessive whilst the other is dominant. This would be the case in a heterozygous genotype. Hope this helps
This may cause a lighter red or a darker blonde. actually that isn't true. it depends on which one is the dominant trait. which one is homozygous which one is heterozygous. it all depends.
In genetics, a trait is considered dominant when it determines a phenotype over a recessive trait. For example, AA is crossed with AA to make Aa, Aa, Aa, and Aa. If "A" is the dominant trait and "a" is the recessive trait, then since this cross produces heterozygous progeny, they will all show the dominant phenotype. A dominant trait is just how it sounds, it dominates over recessive traits when they are both present.
A recessive trait is the opposite of a dominant trait. A dominant trait is the trait that overpowers another trait- represented by a capital letter. The recessive trait is the trait that is weaker, and being overpowered- represented by a lowercase letter. For example, if one person had a recessive trait for detached earlobes, it would be represented as " aa ",. If someone had a dominant trait for attached earlobes (meaning they had free earlobes), it would be represented as "AA"or " Aa "