It codificates the aminoacid
Císteina in spanish
There are two codons that code for the amino acid phenylalanine: UUU and UUC.
AGU and UCA both code for the amino acid serine - so do the codons AGC, UCU, UCC and UCG. CCA codes for proline - so do CCU, CCC and CCG. Therefore any codons which do not code for the sequence serine-serine-proline will be different. For example: UUC-GCU-AAU will code for a different amino acid sequence
A base substitution mutation in a gene may not always result in a different protein because of redundancy in the genetic code. Some amino acids are encoded by multiple codons, so a mutation may still code for the same amino acid. Additionally, mutations in non-coding regions or silent mutations that do not change the amino acid sequence may not alter the protein product.
It would be UAC. RNA does not use thymine. It replaces it with Uracil. So instead of TAC it will be UAC.
Due to the calculations you make using your genetic code dictionaries, you must go backwards using the third letter of codon and then second and then first. Then, you have your answer for what the amino acid sequence would be for cga gaa guc. Then you just flip cga and guc, keeping gaa in the middle.
There are two codons that code for the amino acid phenylalanine: UUU and UUC.
There are two codons that code for the amino acid phenylalanine: UUU and UUC.
AGU and UCA both code for the amino acid serine - so do the codons AGC, UCU, UCC and UCG. CCA codes for proline - so do CCU, CCC and CCG. Therefore any codons which do not code for the sequence serine-serine-proline will be different. For example: UUC-GCU-AAU will code for a different amino acid sequence
A codon is three bases long - so this section of mRNA would have 4 codons; UGA-UUC-AGU-AAC.Each codon relates to a specific amino acid (but several codons can code for the same amino acid, for example both UUU and UUC code for the amino acid Phenylalanine).Normally if you have four codons, such as this section of mRNA, the maximum number of amino acids you could have would be four. However, the first codon in this section, UGA, is actually a STOP codon. This means that when the ribosome reaches this codon, no further amino acids will be joined.This means that no amino acids could be coded for with this section of mRNA. (If the order of the codons was reversed, making the STOP codon last, then the answer would be three).
Yes, each amino acid has several codons that correspond to it. Please see the related link for a chart which shows this. For example, UUU and UUC both code for Phenylalanine. However, if you are asking if a codon can code for more than one amino acid, the answer is no (but there are exceptions). This means that UUU codes for Phenylalanine - not for any other amino acids. Codons are made in sets of three bases to match the anticodons in corresponding sets of three bases.
A base substitution mutation in a gene may not always result in a different protein because of redundancy in the genetic code. Some amino acids are encoded by multiple codons, so a mutation may still code for the same amino acid. Additionally, mutations in non-coding regions or silent mutations that do not change the amino acid sequence may not alter the protein product.
To match up an RNA sequence to an amino acid one, you have to match up the corresponding letters (which are one of the 4 bases in DNA): RNA: U , A , C , G Will match with: DNA: A , T , G , C RNA is different to DNA because instead of a T it has a U. Therefore your question can't be correct because there are 5 letters in total in yours. If, however, i were to take out the 'T', the answer would be: tacttcttcaagct But this answer could not be correct because all DNA sequences must equal a multiple of 3, because every three letters forms 1 amino acid.
It would be UAC. RNA does not use thymine. It replaces it with Uracil. So instead of TAC it will be UAC.
Due to the calculations you make using your genetic code dictionaries, you must go backwards using the third letter of codon and then second and then first. Then, you have your answer for what the amino acid sequence would be for cga gaa guc. Then you just flip cga and guc, keeping gaa in the middle.
GCT AAG would produce the strand of mRNA of "CGA UUC" CGU AAU UGA CUG
The anticodon sequence would be GAG-UUC-ACG-AAG.
The sequence of amino acids (forming a protein) that result from the mRNA strand CAG-AAG-UUC-CUC-UCG-C would be: Glutamine-Threonine-Phenylalanine-Leucine-Serine Each codon must be three bases long - therefore the end of this mRNA sequence 'C' cannot code for an amino acid. There would also need to be a stop codon at the end to complete translation.