The tennis ball.
But do you know why?
The anser to that is in the relationship between the fomula for a shere's volum and that of it's surface area.
Area is a radius squared function whereas volume is a radius cubed function.
The surface area to volume ratio increases when folds are made in a cell's outer membrane. This increase allows for more efficient exchange of materials with the surroundings because there is more surface area available for interactions.
As a cell increases in size the volume increases much faster than the surface area. The possible answer is C.
increase as well, but at a slower rate than the volume. This is due to the relationship between surface area and volume in a cell. As the cell grows, its surface area to volume ratio decreases, causing it to become less efficient at exchanging nutrients and wastes with its environment.
As a cell grows, its volume increases faster than its surface area. This is because volume increases cubically with size, while surface area only increases quadratically. This can lead to challenges in nutrient exchange and waste removal for larger cells.
By adding elongated extensions to the cell the surface area to volume ratio will be increased. One good example of a type of cell that can get very large but still have adequate oxygen diffusion rates is a neuron, some of which can have meters long axons in some animals.Flatten it. The shape should be as far from spherical, and the cross section as far from circular as possible.
They are spheres. They cannot therefore have different geometrical properties. To alter surface to volume ratios you would need to alter the shape. The study of mathematical shapes is called topology.
They are spheres. They cannot therefore have different geometrical properties. To alter surface to volume ratios you would need to alter the shape. The study of mathematical shapes is called topology.
No. A sphere has the smallest surface to volume ratio possible and a basketball is nearly spherical in shape (it has surface dimpling and seams).
The surface-to-volume ratio is a mathematical relationship between the volume of an object and the amount of surface area it has. This ratio often plays an important role in biological structures. An increase in the radius will increase the surface area by a power of two, but increase the volume by a power of three.
They both increase. The rate of increase of the surface area is equivalent to the rate of increase of the volume raised to the power 2/3.
If you increase the radius, the volume will increase more than the area.
On first analysis, the basketball would appear to have the higher ratio (regardless of units of measure due to its larger size). But the situation could be interpreted as being rather more complicated than that. The tennis ball is thoroughly covered in very fine fibers, and the basketball has a surface that is dimpled. Both surfaces increase the surface area of their respective objects, but the high aspect ratio fibers of the tennis ball are massively more significant in this effect. Thus, when considering the actual surfaces, the correct answer would appear to be the tennis ball, by a fairly large margin.
A standard basketball has a diameter of about 29.5 inches (approximately 74.93 cm). The volume of a basketball can be calculated using the formula for the volume of a sphere: ( V = \frac{4}{3} \pi r^3 ), which results in a volume of about 7,100 cubic centimeters. The surface area can be calculated using the formula ( A = 4 \pi r^2 ), yielding a surface area of approximately 2,900 square centimeters.
increase surface area for a given volume
the volume increase 8 times
As the diameter of a cell increases, its surface area increases at a slower rate compared to its volume. This means that a larger cell has a smaller surface area-to-volume ratio, which can affect the efficiency of nutrient exchange and waste removal. Cells with lower surface area-to-volume ratios may struggle to adequately support their metabolic needs.
The surface area to volume ratio increases when folds are made in a cell's outer membrane. This increase allows for more efficient exchange of materials with the surroundings because there is more surface area available for interactions.