You get 1BB:2Bb:1bb.
i think you are asking for the outcome of the offspring, yes? The meathod that i know is to use a punnent square. A punnet square uses the probability to test the genotype (genetic makeup) and phenotype (physical characteristics. You can Google "punnet square" if you wish, to get a full description and how to make one. Here are my results*: there is a... 100% chance of a baby black rabbit (assuming that the black hair is domonant) 75% chance the baby will be homozygous (domonant,pure) 25% chance the baby will be heterozygous (domonant, hybrid) *these results are very general and i am assuming that there is no blending of the traits. (like a gray bunny!) Hope this helped!
A punnet square shows all possible combinations of alleles from two parents and predicts the likelihood of certain genetic outcomes in their offspring. By organizing alleles into different combinations, a punnet square helps demonstrate the principles of Mendelian genetics, including dominant and recessive traits.
The genotype for brown eyes is represented as BB or Bb, while blue eyes are represented as bb. To complete the Punnett Square, you can use the genotypes BB, Bb, Bb, and bb.
A Punnett Square is a diagram used by biologists and geneticists to analyze crossbreeding, i.e. to determine the probability of the possible types of offspring which would result from crossing parents of similar or different genotypes and phenotypes. It is used to show every type of combination possible when one or more maternal and paternal alleles interact, for each gene being studied in the cross. Though not always accurate, this diagram also generally teaches students that are studying genetics how receiving one allele from two different parents does not always have a straightforward outcome. It shows students that there are a large number of possibilities when paternal and maternal alleles interact, especially when one or more parent has an unknown allele.
Reginald Punnett was a British geneticist who co-developed the Punnett square, a visual representation used to predict the outcomes of genetic crosses. His work in pea plant genetics with William Bateson helped lay the foundation for the field of genetics.
Depends on the genetic make up of the parent organisms. for example: Aa x Bb yeilds-> AB, Ab, aB, & ab Just draw a punnet square and solve that way
A punnet square is a box of 4 sections
An example of a punnet square is if you have the heterozygous Bb genotype. The punnet square would have a big B and a little B at the top and on the side. The first square would be BB, the second one would be Bb, the third would be Bb, and the fourth would be bb. the possibility that the child has the bb genotype is 1/4.
A banana is a good example of a punnet square since it has absolutely nothing to do with a punnet square.
The likely-hood of receiving either a dominant or recessive gene from each parent. One parent might have a Bb and the other parent have bb, where B is for dominant brown eyes. If you put them together, You will have a Bb, Bb, bb, and bb. That means you have a 50% chance of having brown eyes sense bb means you do not have brown eyes.
A punnet square is a box of 4 sections
i think you are asking for the outcome of the offspring, yes? The meathod that i know is to use a punnent square. A punnet square uses the probability to test the genotype (genetic makeup) and phenotype (physical characteristics. You can Google "punnet square" if you wish, to get a full description and how to make one. Here are my results*: there is a... 100% chance of a baby black rabbit (assuming that the black hair is domonant) 75% chance the baby will be homozygous (domonant,pure) 25% chance the baby will be heterozygous (domonant, hybrid) *these results are very general and i am assuming that there is no blending of the traits. (like a gray bunny!) Hope this helped!
the punnet square is used for combining genes of two people or animals to predict the outcome of an offspring
the punnet square is used for combining genes of two people or animals to predict the outcome of an offspring
Well it depends on how many of each that you have. Let's start simple. Let's say your mom has brown eyes which is a dominant gene meaning it has a capital B and your dad has blue eyes which is a recessive gene which means it has a lower case b. So mom can either be Bb or BB in order to have brown eyes, but dad is definitely bb because he has blue eyes. So let's just say mom is BB. So for this punnet square you would only need four squares. On the top two you put a B and a B on each square which stands for mom's gene. On the side of the square you put b and a b on each of the two squares which stand for dad's genes. Now all you do is write the new gene in each box. For the top left hand box you would write bB since that b is what dad gives and B is what mom gives. For the top right hand box you write bB again since that is what mom and dad is giving off. Then you do the bottom two squares the same way. Now let's say we want to add height to this. Dad is tall so he is T. Mom is short so she is t. You use the punnet squares again in the exact same way. Place mom's genes on the top and dad are on the bottom. You can also figure out probabilities of genotypes and phenotypes by doing fractions. Someone who is BB or bb is homozygous (means same) for that gene. Someone who is Bb is heterozygous (means opposite). Anyone who is homozygous dominant (BB) that mates with a homozygous recessive (bb) person will result in a punnet square with ¼ Bb, ¼ Bb, ¼ Bb, and ¼ Bb meaning that all of their children will have brown eyes. Anyone who is homozygous dominant (BB) that mates with a heterozygous (Bb) will have ¼ BB, ¼ Bb, ¼ Bb, and ¼ bb. So ¾ of the children will be brown eyed and ¼ blue eyed. If you have heterozygous (Bb) mate with a homozygous (bb) you will have ½ Bb and ½ bb. Using fractions would be easier if you can't get the punnet squares correct.Below is an example of how to do more than one trait.Ex. In peas, tall (D) is dominant to dwarf (d) and yellow cotyledons (G) is dominant to green (g). If a tall, heterozygous pea plant with green cotyledons is crossed with a dwarf pea plant heterozygous for yellow cotyledons, what will be the phenotypic results in the progeny?Ddgg x ddGgDg dg x dG dgdGdgDgDdGgDdggdgddGgddgg½ D ½ d 1g ½ DgProbability of tall ½Probability of short ½Yellow ½Green ½Tall and yellow (1/2 x ½)= ¼Tall and green (1/2 x ½)= ¼Dwarf and yellow (1/2 x ½)= ¼Dwarf and green (1/2 x ½)= ¼
in your face
no