Using a Punnett square, you can calculate the genotype and phenotype of two dihybrid plants.
For example, if you have two heterozygous individuals for two dominant traits (we'll pretend the genotype is YyRr), put them into a Punnett square, and you'll get these results:
YYRR: 1, YYRr: 2, YYrr: 1
YyRR: 2, YyRr: 4, Yyrr: 2
yyRR: 1, yyRr: 2, yyrr: 1
Phenotypes expressed:
Dominant for both traits: 9/16
Dominant for trait 1: 3/16
Dominant for trait 2: 3/16
Recessive for both traits: 1/16
Therefore, the ratio would be 9:3:3:1
Both heterozygous and homozygous dominant genotypes have the same dominant allele, resulting in a similar overall phenotype. The difference lies in the fact that heterozygous individuals have one dominant and one recessive allele, leading to a different genotype than homozygous dominant individuals who have two dominant alleles.
The probability of obtaining a dominant phenotype from self-fertilization of a heterozygous individual is 75%. This is because in a heterozygous individual, there is a 50% chance of passing on the dominant allele and a 50% chance of passing on the recessive allele. With self-fertilization, the possible combinations are: 1 dominant allele (25%), 2 dominant alleles (50%), and 1 recessive allele (25%). Dominant phenotype will be expressed if there are one or more dominant alleles present.
Genotype: AA - The phenotype is homozygous dominant, exhibiting the dominant trait. Genotype: Aa - The phenotype is heterozygous, exhibiting the dominant trait. Genotype: aa - The phenotype is homozygous recessive, exhibiting the recessive trait.
No. Parents with the dominant phenotype might be heterozygous in their genotype. This means they could carry both the dominant and recessive allele for a trait. So they could both pass the recessive allele to an offspring, who would then have the homozygous recessive genotype and recessive phenotype.
No
Homozygous dominant and heterozygous both are a dominant phenotype.
Both heterozygous and homozygous dominant genotypes have the same dominant allele, resulting in a similar overall phenotype. The difference lies in the fact that heterozygous individuals have one dominant and one recessive allele, leading to a different genotype than homozygous dominant individuals who have two dominant alleles.
The dominant allele is the one that determines the phenotype in a heterozygous individual.
it would be whatever the dominant phenotype is... heterozygous would mean having Gg so if G is green and g is white you would have a green plant if the genotype is heterozygous codominance
The probability of obtaining a dominant phenotype from self-fertilization of a heterozygous individual is 75%. This is because in a heterozygous individual, there is a 50% chance of passing on the dominant allele and a 50% chance of passing on the recessive allele. With self-fertilization, the possible combinations are: 1 dominant allele (25%), 2 dominant alleles (50%), and 1 recessive allele (25%). Dominant phenotype will be expressed if there are one or more dominant alleles present.
Heterozygous dominant.D = dominantd = recessiveSame as out breeding for cross with other heterozygous dominant.Dd X DdDDDdDddd
Genotype: AA - The phenotype is homozygous dominant, exhibiting the dominant trait. Genotype: Aa - The phenotype is heterozygous, exhibiting the dominant trait. Genotype: aa - The phenotype is homozygous recessive, exhibiting the recessive trait.
Condominance and Incomplete Dominance.
There is a 50% chance of a homozygous dominant and a 50% chance of a heterozygous.
No. Parents with the dominant phenotype might be heterozygous in their genotype. This means they could carry both the dominant and recessive allele for a trait. So they could both pass the recessive allele to an offspring, who would then have the homozygous recessive genotype and recessive phenotype.
The phenotype will show the dominant trait. All dominant traits mask recessive ones; If the genotype is heterozygous (One dominant and one recessive) the organism's phenotype will be dominant.
No