You can find more information on inheritance on scienceprimer.com/x-linked-inheritance
A heterozygous genotype (e.g. Aa) is not true-breeding because it carries two different alleles for a trait and can produce offspring with different genotypes when crossed. True-breeding genotypes are homozygous for a particular trait (e.g. AA or aa) and will consistently produce offspring with the same genotype when crossed.
In this case, the genotype of the white-eyed male fruit fly would be XwY, and the genotype of the heterozygous red-eyed female fruit fly would be XRXw. The expected ratio of genotypes in the offspring would be 1:1 for XRY (red-eyed males) and XRXw (red-eyed females).
If both oompahs are heterozygous (Oo), there are three possible genotypes that would result in offspring with orange faces: OO, Oo, and oO. Therefore, 75% of the offspring from this cross would have orange faces.
The possible genotypes of the offspring are Bb (heterozygous blue) and bb (white). The possible phenotypes are blue and white flowers. Each offspring will inherit one allele from each parent, resulting in a 50% chance of being blue (Bb) and 50% chance of being white (bb).
If a heterozygous tall pea plant, Aa, is crossed with a homozygous plant, AA, for the trait, you will have a one in one in four chance of the offspring being heterozygous. You will need to create a square and plug the traits in to see what the odds are.
You can find more information on inheritance on scienceprimer.com/x-linked-inheritance
A heterozygous genotype (e.g. Aa) is not true-breeding because it carries two different alleles for a trait and can produce offspring with different genotypes when crossed. True-breeding genotypes are homozygous for a particular trait (e.g. AA or aa) and will consistently produce offspring with the same genotype when crossed.
In this case, the genotype of the white-eyed male fruit fly would be XwY, and the genotype of the heterozygous red-eyed female fruit fly would be XRXw. The expected ratio of genotypes in the offspring would be 1:1 for XRY (red-eyed males) and XRXw (red-eyed females).
If both oompahs are heterozygous (Oo), there are three possible genotypes that would result in offspring with orange faces: OO, Oo, and oO. Therefore, 75% of the offspring from this cross would have orange faces.
Their offspring will be heterozygous recessive.
The possible genotypes of the offspring are Bb (heterozygous blue) and bb (white). The possible phenotypes are blue and white flowers. Each offspring will inherit one allele from each parent, resulting in a 50% chance of being blue (Bb) and 50% chance of being white (bb).
Punnet square
In pea plants, the yellow color (Y) is typically dominant over the green color (y). If a heterozygous yellow pea plant (Yy) is crossed with a green pea plant (yy), the possible genotypes of the offspring would be 50% heterozygous yellow (Yy) and 50% homozygous green (yy). Therefore, the offspring would exhibit a 50% chance of being yellow and a 50% chance of being green.
If a heterozygous tall pea plant, Aa, is crossed with a homozygous plant, AA, for the trait, you will have a one in one in four chance of the offspring being heterozygous. You will need to create a square and plug the traits in to see what the odds are.
If the flowers are something like PP (purple) and pp (pink), then the flowers will be Pp if you do the traditional square used in most high school classes.
they are fine; expected ratios might not been seen simply due to chance
The term "hybrid" in biology means one who carries different alleles for the same trait. For example, a hybrid plant's genotype for height is Hh. When crossing two hybrids, we are performing this operation: Hh x Hh. The offsprings' genotypes can vary from: HH Hh hh