from a medical stand point green eyes are very rare in general. green eyes with black hair is very very rare because usually dark hair means dark eyes.
Picking from this set though: I think it is 8+(13-8)+(15-8) / 28
8+5+7. 20/28, = 5/7 or 0.714. Good odds.
Black seed cotton has smoother seeds and green seed cotton has spiky seeds. This makes it harder to clean green seed cotton than it is to clean black seed, because the green seeds will stick to the cotton fibers.
Yes. Blue eyes are a recessive genetic trait, which means that a brown- or green-eyed person can still carry a gene for blue eyes. In this case, the blue-eyed gene is recessive, or subordinate, to the green- or brown-eyed gene. To be blue-eyed, an individual must have a recessive blue-eyed gene from both its mother and father.
Nvidia.
Type O Negative
Whichever gene is more dominant will pass on to the child. EDIT: Whoever posted the above answer is incorrect. SHORT ANSWER: Brown eyes are more likely, but it's still possible. Indepth: Brown eyes will always be the dominant gene over green. Gene dominance doesn't work on a personal level. It just depends which combination of genes the parents pass. This is why you see siblings with different eye colors. The dad could have brown eyes and still be carrying a recessive gene for green eyes. If he passes those genes instead, then green eyes are much more likely. Likewise, the child could end up with brown eyes while carrying the mother's recessive gene for green eyes, and then pass it to their child. ("skipping a generation")
This is a law of addition probability which states that the probability of A or B equals the probability of A plus the probability of B minus the probability of A and B. Written in mathematical terms, the equation is: P(AorB) = P(A) + P(B) - P(AnB) where P(AnB) = 0 (since you can not pull out a green and black ball at the same time). Let P(A) = Probability of drawing the green ball & let P(B) = Probability of drawing the black ball. Total outcomes is 17. So, P(A) = 4/17 & P(B) = 6/17. Therefore P(green or black) = 4/17 + 6/17 = 10/17.
There are 8 marbles that aren't black, out of a total of 12 marbles, so the probability is 8/12 or 2/3.
Chromatography
the probability is you'd get a green marble any other color is impossible. So, the probability is certain
If there is 3 blue 2 red and 4 green. What is the probability of getting green?
1 in 52
3/12*3/11 = 9/132, or 6.818%.
The answer depends on how many are picked,whether they are returned after picking and whether the picking is done at random. In a single random selection the probability is 17/25.
The probability is 0.625
The probability is zero, because there are no red balls in the bag.
There is a 60% chance you will choose a black, 20% chance of a green, and 20% chance of a blue.
Step 1: Count the total number of sweets in a "bag"There are 3 yellow, 5 green, 7 red, 4 purple and 1 black sweets. Add all these values up to obtain 20 sweets total.Step 2: Determine the probability of the given eventSince we want to determine the probability of selecting a black sweet out of a "bag", we have:1 / 20 = number of black sweets / total number of sweets