The Allele that causes guinea pigs to be brown in color is a dominant one and the white guinea pig's alleles are recessive. The brown guinea pig had two dominant alleles for brown color and the white guinea pig had two for white. Since offspring get one allele from each parent they have one dominant brown allele and one recessive white allele. Since the dominant trait is the one that is going to be apparent, it would only make sense for all the offspring to be brown in color.
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The black-coated animal from the initial cross must have been heterozygous (Bb), as it passed on a black allele to all offspring. The white-coated animal from the cross was homozygous recessive (bb). The offspring all inherited one black allele from the black-coated parent and one white allele from the white-coated parent, resulting in a genotype of Bb for all offspring and a black coat color.
All the offspring will have red eyes because the trait for red eyes is dominant and the female is heterozygous (carrying one dominant red eye allele). White eyes are recessive, so the offspring would need to inherit two white eye alleles to have white eyes.
The possible genotypes of the offspring are Bb (heterozygous blue) and bb (white). The possible phenotypes are blue and white flowers. Each offspring will inherit one allele from each parent, resulting in a 50% chance of being blue (Bb) and 50% chance of being white (bb).
If you crossed a black hen/roo with a white hen/roo, the offspring would NOT be blue. If he was recessive white, the chicks would be black. If he was dominant white, the chicks would be white with some black "smudges" or "spots". The only way to produce 100% blue chicks is to cross a black roo over splash hens or a splash rooster over black hens.
This is probably the result of the brown genes being dominant and the white genes being recessive. this is correct.
4 offsprings
If a homozygous black guinea pig (BB) is crossed with a homozygous white guinea pig (bb), all offspring will inherit one black allele (B) from the black parent and one white allele (b) from the white parent, resulting in heterozygous offspring (Bb). Since black fur is dominant over white fur, all offspring will have black fur. Therefore, the probability of an offspring having black fur is 100%.
The black guinea pig is likely heterozygous (Bb) for coat color, while the white guinea pig is homozygous recessive (bb). The black guinea pig passes on a black allele to all offspring, resulting in 4 black (Bb) and 2 white (bb) offspring.
No idea i am guessing it is kinda like people. if a black and a white cross it is a 50/50 chance the child will be black or white so its unpredictable it was a 50/50 chance the baby pigs would be blacks or albinos. hope this helps YOU ARE SO RACIST!!!!!
Half of the offspring, or 100 rabbits, would be expected to be white when offspring from a heterozygous brown rabbit and a white rabbit are produced. This is due to the dominant-recessive inheritance pattern where brown is dominant and white is recessive.
no dont let them
depends if the black fur gene is dominant.. if it is... then yu would cross BB with bb making all heterozygous genotypes(Bb) therefore, having all possible offspring with black fur so theres a 100% probability of offspring with black fur(:
If two true-breeding pea plants are crossed their offspring will show the dominant trait. The flowers will be purple or light purple.
i have no idea what you are talking about!
Guinea pigs should have a white salt lick, as brown or colored salt licks may contain added ingredients that are harmful to their health. White salt licks are pure and safe for guinea pigs to consume in moderation.
White fur color is recessive and brown is dominant. The white mouse has a genotype of bb and the brown mouse has a genotype of BB. All offspring would be heterozygous with a genotype of BB and brown fur.