The surface area of a 100 mm dish is approximately 314 square millimeters.
The surface area of a cube with side length ( s ) is ( 6s^2 ) and the volume is ( s^3 ). For a cube with side length 2 cm, the surface area is ( 6(2^2) = 24 ) cm(^2) and the volume is ( 2^3 = 8 ) cm(^3). The ratio of surface area to volume for this cube is ( \frac{24}{8} = 3 ).
1 centimeter equals 10 mm and 1 millimeter equals 0.1 centimeter. If you know the diameter in mm, divide by 10 to find cm.
Agar is a gelatinous substance extracted from seaweed. One of its many uses is to solidify nutrient broth used in growing bacteria on a petri dish. A petri dish is a two piece clear glass or plastic dish which keeps dirt or dust from falling into the sterile medium, but allows air to enter and carbon dioxide to leave.
I HOPE I HELP villi are tiny, finger-like projection that are approximately 0.5-1 mm in lenght and come out from the wall of the small intestine. they increase the surface area and allow for bettre absorption of digested food into the blood system I HOPE I HELPED U LOVE A BIEBER BABE <3
The biggest organ is the skin. Not only does it have more surface area than any other organ, it weighs the most as well. Our skin accounts for about 15 percent of our total body weight. It has a surface area of 1.5-2.0 square meters, most of it is between 2-3 mm thick.
To calculate the surface area of an ISMB 200, you need to know its dimensions. The ISMB 200 is an Indian Standard Medium Weight Beam, and its dimensions are: Height: 200 mm Width: 100 mm Flange thickness: 10.2 mm Web thickness: 5.7 mm Length: Typically supplied in standard lengths of 6, 9, 12, or 15 meters To calculate the surface area of an ISMB 200, you need to find the surface area of each of its parts separately and then add them up. The surface area of the flanges and the web can be calculated as follows: Surface area of each flange = Width × Flange thickness × 2 = 100 mm × 10.2 mm × 2 = 2040 mm² Surface area of the web = Height × Web thickness = 200 mm × 5.7 mm = 1140 mm² Total surface area of an ISMB 200 = Surface area of both flanges + Surface area of the web = (2040 mm² + 2040 mm²) + 1140 mm² = 5220 mm² Therefore, the surface area of an ISMB 200 is 5220 square millimeters.
To calculate the volume of a dish, you can use the formula for the volume of a rectangular prism, which is length × width × height. If the dimensions of the dish are given in millimeters (mm), simply multiply the three measurements together. For example, if the dish measures 100 mm x 50 mm x 20 mm, the volume would be 100 mm × 50 mm × 20 mm = 100,000 mm³. If the dish is a different shape, the formula would vary accordingly.
A cylinder if the diameter is 124 mm and the length is 170 mm has a surface area of 90,377.34mm2
Not clear which area you want. The surface area of the cylinder can only be determined if you give the length of the cylinder as well as its diameter. As you don't give this I conclude you want the area of the ends only. Each end will be the difference between the area of the 100 mm circle and the 30 mm circle. 100 mm diameter area = 7855 sq mm. 30 mm diameter area = 707 sq mm. Therefore area of end = 7148 sq mm, and you have two ends so total = 14296 sq mm
Total surface area = 2*(LW + WH + HL) = 538.76 sq mm.
Assuming that the jewel case is in the shape of a cuboid, the total surface area is 38280 sq mm.
There are 10 milimeters in a centimeter. To get the area of a surface you multiply the lengths of 2 sides adjacent. 10mm x 10mm = 100 mm^2 or 100 square milimeters.
A circle with a radius of 50 mm has an area of 7853.98 square mm
The surface area of cube M is 6(10 mm)2 = 6(100 mm2) = 600 mm2 The surface area of cube N would be 6(20 mm)2 = 6(400 mm2) = 2,400 mm2
Surface area of the ball = 4*pi*342 = 4624*pi square mm
The surface area of a prism is twice the area of the end plus the area of all the sides. For a prism with a polygon cross-section the area of all the sides if given by the perimeter of the cross-section polygon multiplied by the length of the prism. Assuming you have a prism of cross-section that is a rectangle with sides 4 mm and 3 mm, and is 15 mm long (ie it is an oblong), its surface area is: → surface_area = 2 × (4 mm × 3 mm) + 2 × (4 mm + 3 mm) × 15 mm → surface area = 2 × 12 mm² + 14 mm × 15 mm = 234 mm²
76 square mm