What is the Osmolarity of 0.4 M Ammonium3 PO4 explain how?

Answer 1

Molarity = moles of solute / L of solution

Osmolarity = osmoles of solute / L of solution

1 Osmole = 1 mole of osmotically-active solute. (NH4)3PO4 dissociates into 3 NH4+ ions and 1 PO4- ion (total 4 solute particles), so 4 osmoles of (NH4)3PO4 result from 1 mole of (NH4)3PO4. Therefore, because 0.4 moles (NH4)3PO4 per Liter solution are in an 0.4 M solution, 1.6 osmoles of (NH4)3PO4 per Liter solution are present. Thus...

Osmolarity = osmoles of solute / L of solution = 1.6 osmoles of (NH4)3PO4 / L of solution = 1.6 OsM

Answer 2

The osmolarity of 0.4 M Ammonium phosphate ((NH4)3PO4) can be calculated as follows:
Ammonium phosphate dissociates into 3 ammonium ions (NH4+) and 1 phosphate ion (PO4^3-).
Thus, the total number of particles in solution is 4 (3 + 1).
Osmolarity is calculated as Molarity x number of particles, so in this case, it would be 0.4 M x 4 = 1.6 Osm.