If the parents were AA and AA for example then the phenotype ratio will be 1 A (the dominant allele).
The genotype will be 1Aa.
if you are doing 7th grade life science, it would be B)all dominant because it has FF, FF, Ff, and Ff. All of these has dominant F, so it is all dominant.
It is not fully known whether it is a recessive gene that causes spots on a cat, but fom a mathematical point of view, you would only get striped offspring.
Any cross of parents for a single trait where the dominant allele completely masks any expression of the recessive allele as follows:Parents are both heterozygous for the trait. For example Aa X Aa produces 75% of offspring with the dominant phenotype and 25% with the recessive phenotype.One parent is heterozygous for the trait and the other parent is homozygous recessive. For example: Aa X aa produces 50% offspring with the dominant phenotype and 50% offspring with the recessive phenotype.If the trait is co-dominant/non-dominant a heterozygote would have the median characteristic and a homozygote could be either of two phenotypes. If T is tall and t is short the Tt offspring would bemedium in this example. The way to produce offspring with only two phenotypes would be to cross a heterozygous parent with a homozygous parent. For Example:Tt X tt cross would produce 50% tt (short) offspring and 50% Tt (medium) offspring. A TT X Tt cross would produce 50% TT (tall) offspring and 50% Tt (medium) offspring.
Punnett Squares are useful because they allow you to see the chance of what genes will be handed down to the offspring. They are a quick and easy way to determine the chance of a offspring having a certain characteristic.
It is important to remember that the factors inherited by the first offspring of a cross have no effect at all on other offspring of that cross. For example, there is a 25% probability that offspring of a cross betweet two hybrid bean plants will inherit the factos RR. If one offspring inherits RR, there is still a 25% probability that the next offspring will also inherit RR.
3
25%
Well considering that chestnut is recessive the foal most likely would be black, although it could be possible to get a bay foal.
The answer is six.
R R r Rr Rr r Rr Rr That is the Punnet Square. The genotype will be 100% Rr in the cross. The phenotype will be whatever phenotype is constituted by your dominant allele.
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Don't give us the options then!! If one parent had 2 dominant genes then all offspring would have dominant phenotype, the same goes for both parents having dominant genes.
possible mendelian ratios for monohybrid cross genotype is 1:2:1 and phenotype is 3:1
Back-cross it with itself. If the offspring are all same as parent phenotype, the individual is said to "breed true".
A dihybrid cross results in 16 squares. Therefore one square represents 1/16 (or 6.25%) of the expected offspring.
if you are doing 7th grade life science, it would be B)all dominant because it has FF, FF, Ff, and Ff. All of these has dominant F, so it is all dominant.
The phenotype will show the dominant trait. All dominant traits mask recessive ones; If the genotype is heterozygous (One dominant and one recessive) the organism's phenotype will be dominant.