What is the mechanism of Reimer tiemann reaction when we use ccl4 in place of chcl3?

Answer 1

The Reimer Tiemann reaction wil not proceed as normal if we use tetrachloromethane; the usual mechanism involves deprotonation of chloroform followed by loss of a chloride ion from the anion to yield dichlorocarbene. With no hydrogens to be removed, tetrachloromethane will not do this.

It is, however, conceivable that dichlorocarbene could be generated from CCl4 by reaction with zinc, leading to a pseudo-Reimer-Tiemman reaction.

Answer 2

When CCl4 is used instead of CHCl3 in the Reimer-Tiemann reaction, it acts as the chlorinating agent. In the presence of a base like hydroxide, CCl4 is converted to PhCOCl, a chloroformate, which reacts further to form the desired product. The presence of CCl4 can lead to the formation of additional side products due to its higher reactivity compared to CHCl3.

Answer 3

This is an organic reaction used to convert a phenol to an o-hydroxy benzaldehyde. This mechanism entails the abstraction of the proton from chloroform to form trichloro carbanion.

Answer 4

yes