The gametes would be AB, Ab, aB, ab which would go both across the top and down the side of the punnett square.
The genotypic ratio is 1:2:1:2:4:2:1:2:1
1AABB: 2AABb: 1 AAbb: 2 AaBB: 4AaBb: 2Aabb: 1aaBB: 2aaBb: 1aabb
The phenotypic ratio is 9:3:3:1
9AB: 3Ab:3aB:1ab phenotypes
The genotypes of this cross are:AA - 25%Aa - 50%aa - 25%The phenotypes of this cross are:Dominant trait (A) - 75%Recessive trait (a) - 25%A ratio of dominant to recessive phenotypes - 3:1
The phenotypic ratio of the cross AaBb x AaBb is 9:3:3:1, which represents the different possible combinations of genotypes for the offspring based on the principles of Mendelian genetics. This ratio indicates that 9 out of 16 offspring will exhibit the dominant phenotype for both traits, while 3 out of 16 will exhibit one dominant and one recessive phenotype, 3 out of 16 will exhibit the other dominant and recessive phenotype, and 1 out of 16 will exhibit both recessive phenotypes.
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For example:Scented (S) is dominant, odorless (s) is recessive, Smooth (O) is dominant, hairy (o) is recessive.a heterozygous scented, smooth-stemmed plant (SsOo) crossed with a fully homozygous odorless, hairy-stemmed plant (ssoo) will get offspring with phenotype ratio 1:1:1:1.Offspring:SsOo (scented, smooth), ssOo (odorless, smooth), Ssoo (scented, hairy), ssoo (odorless, hairy) = 1:1:1:1.
Four different phenotypes can be produced: AABB, AABb, AaBB, and AaBb. This is the result of different combinations of alleles from each parent in the offspring.
Asuming that the F1 generation is heterozygous for a single trait and that the F2 cross is of 2 F1 offspring. Ex. Aa X Aa the phenotypic ratio is 3:1 dominant to recessive. The genotypic ratio is 1:2:1 AA:Aa:aa.
The genotypes of this cross are:AA - 25%Aa - 50%aa - 25%The phenotypes of this cross are:Dominant trait (A) - 75%Recessive trait (a) - 25%A ratio of dominant to recessive phenotypes - 3:1
Generally, if the parents are heterozygous and one allele is dominant over the other there are only 2 phenotypes and 3 genotypes. Parents Aa can produce AA, Aa and aa offspring. If the heterozygous individuals have an intermediate phenotype, then three genotypes and 3 phenotypes are possible. If 2 traits are being studied using heterozygous parents AaBb then the possible Genotypes are AABB, AABb, AAbb, AaBB, AaBb, Aabb, aaBb, aaBB, aabb which is nine genotypes. But there are 4 phenotypes. AABB AABb AaBB AaBb are phenotypically the same. aaBb, aaBB are phenotypically the same. Aabb, AAbb are phenotypically the same. aabb
The phenotypic ratio of the cross AaBb x AaBb is 9:3:3:1, which represents the different possible combinations of genotypes for the offspring based on the principles of Mendelian genetics. This ratio indicates that 9 out of 16 offspring will exhibit the dominant phenotype for both traits, while 3 out of 16 will exhibit one dominant and one recessive phenotype, 3 out of 16 will exhibit the other dominant and recessive phenotype, and 1 out of 16 will exhibit both recessive phenotypes.
The 9/3/3/1 ration is the ratio of phenotypes that are the result of a dihybrid cross. Consider two genes, A and B, that reside on different chromosomes (so that they independently assort). Assume each gene has two alleles. For A, A is dominant and a is recessive, while for the B gene, B is dominant and b is recessive. Now consider a cross between two individuals that are heterozygous for both genes (this is called a dihybrid cross): AaBb X AaBb There are only 4 possible gametes that each individual can produce (in equal proportion): AB Ab aB ab So if we cross the two we get 16 combinations. This will result in 9 possible genotypes: AABB AABb AAbb AaBB AaBb Aabb aaBB aaBb aabb However, there are only 4 possible phenotypes (with proportion in parentheses): Dominant A and B (9/16) (AABB, AABb, AaBB, AaBb) Dominant A, Recessive B (3/16) (AAbb, Aabb) Recessive A, Dominant B (3/16) (aaBB, aaBb) Recessive A, Recessive B (1/16) (aabb)
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For example:Scented (S) is dominant, odorless (s) is recessive, Smooth (O) is dominant, hairy (o) is recessive.a heterozygous scented, smooth-stemmed plant (SsOo) crossed with a fully homozygous odorless, hairy-stemmed plant (ssoo) will get offspring with phenotype ratio 1:1:1:1.Offspring:SsOo (scented, smooth), ssOo (odorless, smooth), Ssoo (scented, hairy), ssoo (odorless, hairy) = 1:1:1:1.
A phenotype is the composite of an organism's observable traits. The answer to the question, the cross that will yield four phenotypes in the 1:1:1:1 ratio is fifty.
The offspring of a cross between organisms with the genotypes AaBb and AaBb would be referred to as a dihybrid cross, focusing on two different gene pairs (A/a and B/b) segregating independently. The resulting offspring would have a genotype ratio of 9:3:3:1 in a typical Mendelian inheritance pattern.
AABB was created in 1947.
Four different phenotypes can be produced: AABB, AABb, AaBB, and AaBb. This is the result of different combinations of alleles from each parent in the offspring.