The gametes would be AB, Ab, aB, ab which would go both across the top and down the side of the punnett square.
The genotypic ratio is 1:2:1:2:4:2:1:2:1
1AABB: 2AABb: 1 AAbb: 2 AaBB: 4AaBb: 2Aabb: 1aaBB: 2aaBb: 1aabb
The phenotypic ratio is 9:3:3:1
9AB: 3Ab:3aB:1ab phenotypes
3/4 show the dominant trait in Aa x Aa
3/4 show the dominant trait in Bb x Bb
(3/4) x (3/4) = 9/16
3/4 AP bio!!!!
there are about 3-4 syllables in a name
9:3:3:1
The genotypes of this cross are:AA - 25%Aa - 50%aa - 25%The phenotypes of this cross are:Dominant trait (A) - 75%Recessive trait (a) - 25%A ratio of dominant to recessive phenotypes - 3:1
These are the phenotypic ratios of each outcome: Dominant A and B: 9/16 Dominant A and recessive B: 3/16 Recessive A and dominant B: 3/16 Recessive A and B: 1/16
You make a box with 4 boxes in it and then you plug in the parents on the top and the side, which is the BBxBb, and match up the alleles (the letters) like coordinates in a graph. BBBBBBBBbBbb
Ab and ab There would be about a 50/50 ratio of each.
two sets of genes on nonhomologous chromosomes
Asuming that the F1 generation is heterozygous for a single trait and that the F2 cross is of 2 F1 offspring. Ex. Aa X Aa the phenotypic ratio is 3:1 dominant to recessive. The genotypic ratio is 1:2:1 AA:Aa:aa.
The genotypes of this cross are:AA - 25%Aa - 50%aa - 25%The phenotypes of this cross are:Dominant trait (A) - 75%Recessive trait (a) - 25%A ratio of dominant to recessive phenotypes - 3:1
Generally, if the parents are heterozygous and one allele is dominant over the other there are only 2 phenotypes and 3 genotypes. Parents Aa can produce AA, Aa and aa offspring. If the heterozygous individuals have an intermediate phenotype, then three genotypes and 3 phenotypes are possible. If 2 traits are being studied using heterozygous parents AaBb then the possible Genotypes are AABB, AABb, AAbb, AaBB, AaBb, Aabb, aaBb, aaBB, aabb which is nine genotypes. But there are 4 phenotypes. AABB AABb AaBB AaBb are phenotypically the same. aaBb, aaBB are phenotypically the same. Aabb, AAbb are phenotypically the same. aabb
The 9/3/3/1 ration is the ratio of phenotypes that are the result of a dihybrid cross. Consider two genes, A and B, that reside on different chromosomes (so that they independently assort). Assume each gene has two alleles. For A, A is dominant and a is recessive, while for the B gene, B is dominant and b is recessive. Now consider a cross between two individuals that are heterozygous for both genes (this is called a dihybrid cross): AaBb X AaBb There are only 4 possible gametes that each individual can produce (in equal proportion): AB Ab aB ab So if we cross the two we get 16 combinations. This will result in 9 possible genotypes: AABB AABb AAbb AaBB AaBb Aabb aaBB aaBb aabb However, there are only 4 possible phenotypes (with proportion in parentheses): Dominant A and B (9/16) (AABB, AABb, AaBB, AaBb) Dominant A, Recessive B (3/16) (AAbb, Aabb) Recessive A, Dominant B (3/16) (aaBB, aaBb) Recessive A, Recessive B (1/16) (aabb)
AABB was created in 1947.
AaBb usually, but can also be AAbb or aaBB depending on what they ask you is heterozygous. To be heterozygous for one trait, it's AaBb. To have a heterozygous genotype, unless specified, it can be any of the above.
AABB
These are the phenotypic ratios of each outcome: Dominant A and B: 9/16 Dominant A and recessive B: 3/16 Recessive A and dominant B: 3/16 Recessive A and B: 1/16
You make a box with 4 boxes in it and then you plug in the parents on the top and the side, which is the BBxBb, and match up the alleles (the letters) like coordinates in a graph. BBBBBBBBbBbb
Ab and ab There would be about a 50/50 ratio of each.
This is called a dihybrid cross in which both parents are heterogeneous.
Ddgg, ddgg, aabb, aabb, ff, ff, fedd, fedd, ddgg, ddgg